实例化异常：没有零参数构造函数吗？

Question

我试图在谷歌地图中显示一个位置地址，但当我为获取地址启动意向服务时，它将显示错误“无法实例化服务”。

我使用此链接显示位置地址。

https://developer.android.com/training/location/display-address.html

这是我的代码：

public class FetchAddressIntentService extends IntentService {
    protected ResultReceiver mReceiver;

    public FetchAddressIntentService(String name) {
        super(name);
    }


    @Override
    protected void onHandleIntent(Intent intent) {
        String errorMessage="";

        Geocoder geocoder=new Geocoder(this, Locale.getDefault());

        Location location = intent.getParcelableExtra(Constants.LOCATION_DATA_EXTRA);



        List<Address> addresses=null;

        try {
            addresses=geocoder.getFromLocation(location.getLatitude(),location.getLongitude(),1);
        } catch (IOException e) {
            errorMessage="unhendle IO exception";
            e.printStackTrace();
        }


        if(addresses==null && addresses.size()==0){
            if(errorMessage.isEmpty()){
                errorMessage="no address found";
            }

            deliverResultToReceiver(Constants.FAILURE_RESULT, errorMessage);
        }
        else{

            Address address=addresses.get(0);
            ArrayList<String> arrayListFrag=new ArrayList<>();

            for (int i=0;i<address.getMaxAddressLineIndex();i++){

                arrayListFrag.add(address.getAddressLine(0));
            }

            deliverResultToReceiver(Constants.SUCCESS_RESULT,
                    TextUtils.join(System.getProperty("line.separator"),
                            arrayListFrag));

        }
    }

    private void deliverResultToReceiver(int successResult, String message) {
        Bundle bundle=new Bundle();
        bundle.putString(Constants.RESULT_DATA_KEY,message);
        mReceiver.send(successResult,bundle);
    }
}

在这里我开始意图服务：

 protected void startIntentService(){
        Intent intent=new Intent(this,FetchAddressIntentService.class);
        intent.putExtra(Constants.RECEIVER, mResultReceiver);
        intent.putExtra(Constants.LOCATION_DATA_EXTRA,mLastLocation);
        startService(intent);
    }


   public void fetchAddressButtonHandler(){
        if(mGoogleApiClient.isConnected() && mLastLocation!=null){
            startIntentService();
        }

   }

Answer 1

您需要向类FetchAddressIntentService添加不带参数的零参数构造函数：

public FetchAddressIntentService() {
    super("FetchAddressIntentService");
}

Answer 2

替换：

public FetchAddressIntentService(String name) {
  super(name);
}

与：

public FetchAddressIntentService() {
  super("whatever you want to use here");
}

（用适合您应用程序的内容替换字符串）