嵌入式类抛出错误中的重复列

Question

我已经使用JPA工具创建了实体类，它已经为没有主键的表创建了两个类。一个是@Entity类，另一个是@嵌入式类，下面是两个类的代码

乡村语言

package com.geolocation.entities;

import java.io.Serializable;
import javax.persistence.*;


/**
 * The persistent class for the countrylanguage database table.
 * 
 */
@Entity
@NamedQuery(name="Countrylanguage.findAll", query="SELECT c FROM Countrylanguage c")
public class Countrylanguage implements Serializable {
    private static final long serialVersionUID = 1L;

    @EmbeddedId
    private CountrylanguagePK id;


    private String isOfficial;

    private String language;


    private float percentage;

    //bi-directional many-to-one association to Country
    
    @ManyToOne
    @JoinColumn(name="CountryCode")
    private Country country;

    public Countrylanguage() {
    }

//  public CountrylanguagePK getId() {
//      return this.id;
//  }
//
//  public void setId(CountrylanguagePK id) {
//      this.id = id;
//  }

    public String getIsOfficial() {
        return this.isOfficial;
    }

    public void setIsOfficial(String isOfficial) {
        this.isOfficial = isOfficial;
    }


    public String getLanguage() {
        return this.language;
    }

    public void setLanguage(String language) {
        this.language = language;
    }

    public float getPercentage() {
        return this.percentage;
    }

    public void setPercentage(float percentage) {
        this.percentage = percentage;
    }

    

    public Country getCountry() {
        return this.country;
    }

    public void setCountry(Country country) {
        this.country = country;
    }

}

**CountrylanguagePK**

package com.geolocation.entities;

import java.io.Serializable;
import javax.persistence.*;

/**
 * The primary key class for the countrylanguage database table.
 * 
 */
@Embeddable
public class CountrylanguagePK implements Serializable {
    //default serial version id, required for serializable classes.
    private static final long serialVersionUID = 1L;

    @Column(insertable=false, updatable=false)
    private String countryCode;

    private String language;

    public CountrylanguagePK() {
    }
    public String getCountryCode() {
        return this.countryCode;
    }
    public void setCountryCode(String countryCode) {
        this.countryCode = countryCode;
    }
    public String getLanguage() {
        return this.language;
    }
    public void setLanguage(String language) {
        this.language = language;
    }

    public boolean equals(Object other) {
        if (this == other) {
            return true;
        }
        if (!(other instanceof CountrylanguagePK)) {
            return false;
        }
        CountrylanguagePK castOther = (CountrylanguagePK)other;
        return 
            this.countryCode.equals(castOther.countryCode)
            && this.language.equals(castOther.language);
    }

    public int hashCode() {
        final int prime = 31;
        int hash = 17;
        hash = hash * prime + this.countryCode.hashCode();
        hash = hash * prime + this.language.hashCode();
        
        return hash;
    }
}

执行时会抛出错误。。

1. org.springframework.beans.factory.BeanCreationExctive：创建名为entityManagerFactory的bean时出错，该bean在类路径资源[org/springFramework/boot/autoconfiure/orm/jpa/HibernateJpaConfiguration.class]中定义：调用init方法失败；嵌套异常javax.persistence.持久性异常：[PeristenceUnit：默认]无法构建HiberNate SessionFactory；嵌套异常org.hibernate.映射异常：实体映射中的重复列：com.geolocation.entities.CountryLanguage列：country_code（应映射为插入="false"更新="false"）
2. 起因：javax.persistence.PeristenceExctive：[PeristenceUnit：默认]无法构建HibernateSessionFactory；嵌套异常org.hibernate.MappingExctive：实体映射中的重复列：com.geolocation.entities.CountryLanguage列：country_code（应映射为插入=假更新=假）
3. 原因：org.hibernate.映射异常：实体映射中的重复列：com.geolocation.entities.CountryLanguage列：country_code（应映射为插入=假更新=假）

Answer 1

可嵌入类型不应使用insertable=false，updateable=false，而应使用@manytone关联的@JoinColumn。