为什么我的if-else语句不能执行？

Question

首先，我发现了另外两条有类似问题的线索。问题在于，他们没有为字符串使用正确的等号，也没有为他们的特定问题正确设置if语句的格式。

在我的任务中，我需要创建一个名为“猪”的游戏，玩家与计算机对决，在掷骰子时先获得100分。如果玩家在一个回合中掷1，他们不会得到额外的分数。如果玩家掷两个1，那么他们将失去所有分数。我还没有对电脑的回合进行编码，只是专注于玩家。请告诉我我做错了什么。提前非常感谢。

import java.util.Scanner;
public class FourFive
{
    public static void main (String[] args)
    {
    Pigs myopp = new Pigs();
    Scanner scan = new Scanner (System.in);
    final int Round = 20;
    int num1, num2;

    int roundTotal = 0;
    int playerTotal = 0;
    int compTotal = 0;
    int win = 100;
    int turnOver = 1;
    Pigs die1 = new Pigs();
    Pigs die2 = new Pigs();
    String play = "y";
    System.out.println("Type y to play");
    play = scan.nextLine();

    while (play.equalsIgnoreCase("y"))
    {
        for (int roll = 1; roll <= 6; roll++)//Each die has 6 sides
        {
            num1 = die1.roll();//rolls first die
            num2 = die2.roll();//rolls second die
            int points = num1 + num2;// adds dies up to get total for this turn
            System.out.println("You roll " + num1 + " and " + num2);

            if (num1 == 1 || num2 == 1)//If either of the dies roll 1, no points 
                points += 0;
            else if (num1 == 1 && num2 == 1)//if both are 1, lose ALL points
                playerTotal = 0;
            else
                System.out.println("you earned " + points + " this round");

            playerTotal += points; total number of points per round added   
            System.out.println("You have a total of " + playerTotal);


            System.out.println("Type y to play");
            play = scan.nextLine();
      }
    }
 }
}

我的输出：

Type y to play
y
You roll 4 and 2
you earned 6 this round
You have a total of 6
Type y to play
y
You roll 6 and 5
you earned 11 this round
You have a total of 17
Type y to play
y
You roll 1 and 1
You have a total of 19 //total should be 0 because of the two 1's
Type y to play
y
You roll 6 and 3
you earned 9 this round
You have a total of 28
Type y to play
y
You roll 1 and 1
You have a total of 30 //total should be 0 because of the two 1's
Type y to play
y
You roll 6 and 4
you earned 10 this round
You have a total of 40
Type y to play
y
You roll 5 and 2
you earned 7 this round
You have a total of 47
Type y to play
y
You roll 5 and 1
You have a total of 53 //shouldn't add any additional points because of the "1"
Type y to play

Answer 1

你的if逻辑有缺陷，有点多余。试试这个：

if (num1 == 1 && num2 == 1) {
    playerTotal = 0;
}
else if (num1 != 1 && num2 != 1) {
    playerTotal += points;
    System.out.println("you earned " + points + " this round");
}
System.out.println("You have a total of " + playerTotal);

Answer 2

如果num1为1，那么第一个If条件为1。它不会检查“else if”条件。类似地，如果num2为1，则if条件取它。所以把你的

        if (num1 == 1 && num2 == 1)//if both are 1, lose ALL points
            playerTotal = 0;
        else if (num1 == 1 || num2 == 1)//If either of the dies roll 1, no points 
            points += 0;
        else
            System.out.println("you earned " + points + " this round");