如何在单个测试的基础上更改模拟实现[Jestjs]

Question

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const myMockedModule = jest.genMockFromModule('../myModule');

myMockedModule.a = jest.fn(() => true);
myMockedModule.b = jest.fn(() => true);

export default myMockedModule;

import myMockedModule from '../myModule';

// Mock myModule
jest.mock('../myModule');

beforeEach(() => {
  jest.clearAllMocks();
});

describe('MyTest', () => {
  it('should test with default mock', () => {
    myMockedModule.a(); // === true
    myMockedModule.b(); // === true
  });

  it('should override myMockedModule.b mock result (and leave the other methods untouched)', () => {
    // Extend change mock
    myMockedModule.a(); // === true
    myMockedModule.b(); // === 'overridden'
    // Restore mock to original implementation with no side effects
  });

  it('should revert back to default myMockedModule mock', () => {
    myMockedModule.a(); // === true
    myMockedModule.b(); // === true
  });
});

以下是我到目前为止所尝试的：

专业人士

• 在第一次调用后恢复到原始实现

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it('should override myModule.b mock result (and leave the other methods untouched)', () => {

  myMockedModule.b.mockImplementationOnce(() => 'overridden');

  myModule.a(); // === true
  myModule.b(); // === 'overridden'
});

null

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代码：

it('should override myModule.b mock result (and leave the other methods untouched)', () => {

  jest.doMock('../myModule', () => {
    return {
      a: jest.fn(() => true,
      b: jest.fn(() => 'overridden',
    }
  });

  myModule.a(); // === true
  myModule.b(); // === 'overridden'
});

专业人士

• 完全控制模拟结果

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const myMockedModule = jest.genMockFromModule('../myModule');

let a = true;
let b = true;

myMockedModule.a = jest.fn(() => a);
myMockedModule.b = jest.fn(() => b);

myMockedModule.__setA = (value) => { a = value };
myMockedModule.__setB = (value) => { b = value };
myMockedModule.__reset = () => {
  a = true;
  b = true;
};
export default myMockedModule;

it('should override myModule.b mock result (and leave the other methods untouched)', () => {
  myModule.__setB('overridden');

  myModule.a(); // === true
  myModule.b(); // === 'overridden'

  myModule.__reset();
});

null

代码：

beforeEach(() => {
  jest.clearAllMocks();
  jest.restoreAllMocks();
});

// Mock myModule
jest.mock('../myModule');

it('should override myModule.b mock result (and leave the other methods untouched)', () => {

  const spy = jest.spyOn(myMockedModule, 'b').mockImplementation(() => 'overridden');

  myMockedModule.a(); // === true
  myMockedModule.b(); // === 'overridden'

  // How to get back to original mocked value?
});

Answer 1

编写测试的一个很好的模式是创建一个安装工厂函数，该函数返回测试当前模块所需的数据。

下面是第二个示例之后的一些示例代码，尽管允许以可重用的方式提供默认值和重写值。

const spyReturns = returnValue => jest.fn(() => returnValue);

describe("scenario", () => {
  beforeEach(() => {
    jest.resetModules();
  });

  const setup = (mockOverrides) => {
    const mockedFunctions =  {
      a: spyReturns(true),
      b: spyReturns(true),
      ...mockOverrides
    }
    jest.doMock('../myModule', () => mockedFunctions)
    return {
      mockedModule: require('../myModule')
    }
  }

  it("should return true for module a", () => {
    const { mockedModule } = setup();
    expect(mockedModule.a()).toEqual(true)
  });

  it("should return override for module a", () => {
    const EXPECTED_VALUE = "override"
    const { mockedModule } = setup({ a: spyReturns(EXPECTED_VALUE)});
    expect(mockedModule.a()).toEqual(EXPECTED_VALUE)
  });
});

必须指出，必须使用jest.resetmodules()重置已经缓存的模块。这可以在每个之前的或类似的teardown函数中完成。