javascript年、月、日倒计时

Question

<script type="text/javascript">

        today = new Date();

        BigDay = new Date("December 25, 2016");
        msPerDay = 24 * 60 * 60 * 1000;
        timeLeft = (BigDay.getTime() - today.getTime());
        e_daysLeft = timeLeft / msPerDay;
        daysLeft = Math.floor(e_daysLeft);
        e_hrsLeft = (e_daysLeft - daysLeft) * 24;
        hrsLeft = Math.floor(e_hrsLeft);
        minsLeft = Math.floor((e_hrsLeft - hrsLeft) * 60);
        // $("#countdown").append("There are only<BR> <H4>" + daysLeft + " days " + hrsLeft + " hours and " + minsLeft + " minutes left </H4> Until December 25th 2020<P>");
        document.write(daysLeft + " days " + hrsLeft + " hours" + minsLeft + " minutes");

</script>

Answer 1

你在正确的轨道上。只要遵循同样的方法，将天除以365，如果超过365，然后做daysLeft模365。

（虽然它不会精确，但它是一个简单的，如果你不需要精确的单位，你可以使用它。）

IE

var today = new Date();

var BigDay = new Date("December 25, 2018");
var msPerDay = 24 * 60 * 60 * 1000;
var timeLeft = (BigDay.getTime() - today.getTime());
var e_daysLeft = timeLeft / msPerDay;
var daysLeft = Math.floor(e_daysLeft);
var yearsLeft = 0;
if (daysLeft > 365) {
  yearsLeft = Math.floor(daysLeft / 365);
  daysLeft = daysLeft % 365;
}
var e_hrsLeft = (e_daysLeft - daysLeft) * 24;
var hrsLeft = Math.floor(e_hrsLeft);
var minsLeft = Math.floor((e_hrsLeft - hrsLeft) * 60);
document.write(yearsLeft + " years " + daysLeft + " days " + hrsLeft + " hours " + minsLeft + " minutes");