Java参数无法识别

Question

我试图从我的jar启动另一个Java进程，我使用的是ProcessBuilder：

File javaHome = new File(System.getProperty("java.home"), "bin");
List<String> javaList = new ArrayList<String>();

ProcessBuilder processBuilder = new ProcessBuilder();
processBuilder.redirectErrorStream(true);
processBuilder.directory(serverDir);
{
    javaList.add(javaHome + File.separator + "java");
    javaList.add("-XX:MaxPermSize=512m");
    javaList.add("-Xmx2048M");

    // -Djava.library.path="natives-win-x64/"
    javaList.add(
        String.format(                          
            "-Djava.library.path=\"natives-%s-%s/\"", 
            //Get system os, 
            //Get system arch
        )
    );

    {
        String classPath = new String();
        for (File library : scanLibrary(new File(serverDir, "libraries"))) {
            String libPath = library.getPath();
            classPath += libPath + ";";
        }

        classPath += new File(new File(serverDir, "binary"), "MainJar.jar").getPath();
        javaList.add("-classpath \\\"" + classPath + "\\\" ");
    }

    javaList.add("my.other.jar.main.class");
}
processBuilder.command(javaList);
processBuilder.start();

错误：无法创建Java虚拟机。错误：发生致命异常。程序将退出。无法识别的选项：-类路径“C:\absoulte\path\library.jar；C:\absoulte\path2\library2.jar；C:\absoulte\path3\library3.jar”

Answer 1

您将--classpath“...”作为单个参数传递。我认为您应该将其指定为两个参数：

javaList.add("-classpath");
javaList.add("\\\"" + classPath + "\\\");

（顺便说一下，我不清楚您是否真的需要所有这些反斜杠...您可能会发现只要javalist.add(classPath)就足够了，或者javalist.add("\“”+classPath+“\”“）。）