如何在listview中获取孩子的位置？

Question

在下面的代码中，如何获取被点击按钮的< code>Button位置？

public class HistoryAdapter extends CursorAdapter {
Button button;
TextView text;

public HistoryAdapter(Context context, Cursor c, int flags) {
    super(context, c, flags);
}

@Override
public View newView(final Context context, Cursor cursor, ViewGroup parent) {
    View view = LayoutInflater.from(context).inflate(R.layout.historylist, parent, false);
    return view;
}

@Override
public void bindView(View view, final Context context, final Cursor cursor) {
    text = (TextView) view.findViewById(R.id.text);
    button = (Button) view.findViewById(R.id.btn);
    String body = cursor.getString(cursor.getColumnIndex("name"));
    text.setText(body);
    button.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

        }
    });

}

}

Answer 1

如果您需要项目在列表中的位置，您可以从传递给onClick方法的View访问它，参考此链接您可以编辑代码：

@Override
public void bindView(View view, final Context context, final Cursor cursor) {
    text = (TextView) view.findViewById(R.id.text);
    button = (Button) view.findViewById(R.id.btn);
    String body = cursor.getString(cursor.getColumnIndex("name"));
    text.setText(body);
    button.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            int position=(Integer)v.getTag();
        }
    });
}

希望有用:)

Answer 2

以下代码应该有效（最后的＜code＞非常重要）：

    @Override
public void bindView(View view, final Context context, final Cursor cursor) {
    text = (TextView) view.findViewById(R.id.text);
    button = (Button) view.findViewById(R.id.btn);
    String body = cursor.getString(cursor.getColumnIndex("name"));
    final int position = cursor.getPosition();
    text.setText(body);
    button.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            doSomething(position);
        }
    });