命名实体图子图

Question

我是JPA 2.1的新手，最近才开始使用命名实体图。对于我的项目，我正在JPA 2.1中映射以下关系：

顺序

我想指示JPA加入并正确获取所有需要的数据。到目前为止，这对订单来说完美无缺 -

以下是我的实体（省略了getter和setter）：

次序

@Entity
@Table(name="ORDERS")
@NamedEntityGraph(
    name = "graph.Order.details",
    attributeNodes = {
        @NamedAttributeNode(value = "details", subgraph = "graph.OrderDetail.product")
    },
    subgraphs = {
        @NamedSubgraph(name = "graph.OrderDetail.product", attributeNodes = @NamedAttributeNode("product"))
    }
)

public class Order implements Serializable{
  @Id
  @Column(name = "orderNumber")
  private Long number;

  @Column(name = "orderDate")
  private Date date;

  @OneToMany(mappedBy = "order")
  private List<OrderDetail> details;
}

订单明细

@Entity
@Table(name = "orderdetails")
public class OrderDetail implements Serializable{

   @ManyToOne(fetch = FetchType.LAZY)
   @JoinColumn(name = "orderNumber")
   @Id
   private Order order;

   @ManyToOne(fetch = FetchType.LAZY)
   @JoinColumn(name = "productCode", nullable = false)
   @Id
   private Product product;

   @Column(name = "orderLineNumber")
   private int lineNumber;

   @Column(name = "quantityOrdered")
   private int quantity;

产品

@Entity
@Table(name = "products")
class Product {
    @Column(name = "productCode")
    @Id
    private String code;

    @Column(name = "quantityInStock")
    public int quantity;

    @ManyToOne
    @JoinColumn(name = "productLine")
    private ProductLine line;

产品线

@Entity
@Table(name = "productlines")
public class ProductLine {
    @Id
    @Column(name = "productLine")
    private String line;

    @Column
    private String textDescription;

Answer 1

每个＜code＞namedAttribute节点。

@Entity
@Table(name="ORDERS")
@NamedEntityGraph(
    name = "graph.Order.details",
    attributeNodes = {
        @NamedAttributeNode(value = "details", subgraph = "graph.OrderDetail.product")
    },
    subgraphs = {
        @NamedSubgraph(name = "graph.OrderDetail.product", attributeNodes = @NamedAttributeNode(value = "product", subgraph = "graph.Product.productLine")),
        @NamedSubgraph(name = "graph.Product.productLine", attributeNodes = @NamedAttributeNode("line"))
    }
)

Answer 2

您可以使用动态实体图创建多级实体图。我正在使用jpa 2.2和Hibernate 5.3.7，我能够创建实体图并获取高达3级的数据。我希望这对下一关也有用。下面是代码片段。有关更多详细信息和实际代码，您可以查看我的github repo:https://github . com/vaneetkataria/Jpa-Hibernate/blob/master/jdbcToJpaMigration/src/test/Java/com/katariasoft/technologies/jpaHibernate/entity/fetch/entity graph/dynamic/multi instructorsdynamicetygrpahtests . Java

代码段：

@SuppressWarnings("unchecked")
    @Test
    @Rollback(false)
    public void fetchInstrctrsIdProofVehiclesStudentsTheirInstructorsVehiclesAndTheirDocuments() {
        doInTransaction(() -> {
            EntityGraph<Instructor> instructorGraph = em.createEntityGraph(Instructor.class);
            instructorGraph.addAttributeNodes(Instructor_.idProof, Instructor_.vehicles);
            Subgraph<Student> studentSubgraph = instructorGraph.addSubgraph(Instructor_.STUDENTS);
            studentSubgraph.addAttributeNodes(Student_.instructors);
            Subgraph<Vehicle> vehicleSubgraph = studentSubgraph.addSubgraph(Student_.VEHICLES);
            vehicleSubgraph.addAttributeNodes(Vehicle_.documents);
            TypedQuery<Instructor> query = em.createQuery("select i from Instructor i ", Instructor.class)
                    .setHint(EntityGraphUtils.FETCH_GRAPH, instructorGraph);
            List<Instructor> instructors = query.getResultList();
            if (Objects.nonNull(instructors))
                instructors.forEach(instructor -> {
                    IdProof idProof = instructor.getIdProof();
                    Set<Vehicle> vehicles = instructor.getVehicles();
                    Set<Student> students = instructor.getStudents();
                    System.out.println(instructor);
                    System.out.println(idProof);
                    if (Objects.nonNull(vehicles))
                        vehicles.forEach(v -> System.out.println(v.getVehicleNumber()));
                    if (Objects.nonNull(students))
                        students.forEach(s -> System.out.println(s.getName()));
                });
        });
    }

Answer 3

简单的答案是，你不能这样做，因为使用当前的JPA实现，你最终会做两个单独的查询，并且不得不处理笛卡尔积。JPA的一些未来版本可以扩展为包括更多级别的子图，但就目前而言，它没有。有一个 JPA SPEC 组适用于下一版本的 JPA。请随时在那里提交您的请求/建议。

在StackOverflow上有另一个相同问题的参考。