为什么在android系统中，每次触碰任何一个通知都会显示最后一个通知

Question

我尝试在android应用程序中创建通知。创建一个事务后，我调用“shownotification”方法在设备中显示通知。

public void showNotification(String screen, String message) {
    NotificationManager notificationManager = (NotificationManager) getSystemService(NOTIFICATION_SERVICE);
    Intent intent = new Intent(this, MainActivity.class);
    intent.putExtra("screen", screen);
    intent.putExtra("message",message);
    int id = 1;
    try {
        // get latest id from SQLite DB
        id = DbManager.getInstance().getIntDbKeyValue("notif_id");
        if (id < 1) {
            id = 1;
        }
    } catch (Exception e) {
    }
    intent.putExtra("notif_id", id + "");

    intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_SINGLE_TOP);
    PendingIntent pIntent = PendingIntent.getActivity(this, 0, intent, PendingIntent.FLAG_UPDATE_CURRENT);
    Notification n = new Notification.Builder(this).setContentTitle(getString(R.string.app_name)).setContentText(message)
            .setSmallIcon(R.drawable.ic_launcher).setContentIntent(pIntent).setAutoCancel(true)
            .setStyle(new Notification.BigTextStyle().bigText(message))
            .build();
    // set next running id into SQLite DB
    DbManager.getInstance().setDbKeyValue("notif_id", (id + 1) + "");
    notificationManager.notify(id, n);
}

@Override
protected void onNewIntent(Intent intent) {
    super.onNewIntent(intent);
    try {
        checkIntent(intent);
    } catch (Exception e) {
        e.printStackTrace();
    }
}

private void checkIntent(Intent intent) {
        try {
            int id = Integer.parseInt(intent.getStringExtra("notif_id"));
            if (id > 0 ) {
                String s = intent.getStringExtra("screen");
                if ("XXXXXX".equalsIgnoreCase(s)) {
                    Fragment f = new MonitoringFragment();
                    Bundle bundle = new Bundle();
                    bundle.putString("message", intent.getStringExtra("message"));
                    f.setArguments(bundle);
                    showFragment(f, false);
                }else{
                    showFragment(new XxxxFragment(), false);
                }
            }
        } catch (Exception e) {
        }
}

PendingIntent pIntent=PendingIntent.GetActivity(this,0,intent,PendingIntent.Flag_Update_Current)；

如果有其他方法不保留每个通知及其notificationId和消息？

Answer 1

我找到了为每个意图添加randon requestCode而不是为每个意图使用0的解决方案。

int requestCode=new Random（）.nextint（）；
PendingIntent pIntent=PendingIntent.getActivity（this,requestCode,intent,PendingIntent.flag_update_current)；