如何排序实例类的列表取决于它在省道或颤振[重复]中的属性

Question

class Contact {
    Contact({
        this.id,
        this.name,
        this.phone,
        this.job,
        this.company,
        this.image,
        this.email,
    });

    int? id;
    String? name;
    String? phone;
    String? job;
    String? company;
    String? image;
    String? email;

}

问题是，如何通过比较contact.name对列表进行排序？因为我想对列表进行A-Z升序排序

Answer 1

可以将比较函数传递给list.sort。

someobjects.sort((a,b)=>a.someproperty.compareto(b.someproperty))；

或者List mList=(mList.sort（））.reversed.tolist（）；