使用Django使用JSON API数据

Question

从Django应用程序中，我可以从单独的Restful API中使用数据，但是过滤呢？下面返回所有书籍及其数据。但如果我只想抓取作者、日期等的书怎么办？我想传递一个作者的名称参数，例如.../authors-name或/？author=name，并只返回json响应中的参数。这可能吗？

views.py

def get_books(request):
    response = requests.get('http://localhost:8090/book/list/').json()
    return render(request, 'books.html', {'response':response})

那么有没有办法像模型对象一样进行过滤呢？

Answer 1

我能想到三种方法：

1. 可以使用Python的筛选器，并附加一些代码。
2. QueryableList，它是我见过的最接近ORM的列表。
3. 查询筛选器，它采用更实用的方法。

您可以编写一个函数，返回告诉您列表元素是否匹配的函数，并将生成的函数传递到filter中。

def filter_pred_factory(**kwargs):

    def predicate(item):
        for key, value in kwargs.items():

            if key not in item or item[key] != value:
                return False

        return True

    return predicate

def get_books(request):
    books_data = requests.get('http://localhost:8090/book/list/').json()
    pred = filter_pred_factory(**request.GET)
    data_filter = filter(pred, books_data)

    # data_filter is cast to a list as a precaution
    # because it is a filter object,
    # which can only be iterated through once before it's exhausted.
    filtered_data = list(data_filter)
    return render(request, 'books.html', {'books': filtered_data})

from QueryableList import QueryableListDicts

def get_books(request):
    books_data = requests.get('http://localhost:8090/book/list/').json()
    queryable_books = QueryableListDicts(books_data)
    filtered_data = queryable_books.filter(**request.GET)
    return render(request, 'books.html', {'books':filtered_data})

from query_filter import q_filter, q_items

def get_books(request):
    books_data = requests.get('http://localhost:8090/book/list/').json()
    data_filter = q_filter(books_data, q_items(**request.GET))

    # filtered_data is cast to a list as a precaution
    # because q_filter returns a filter object, 
    # which can only be iterated through once before it's exhausted.
    filtered_data = list(data_filter)
    return render(request, 'books.html', {'books': filtered_data})