在改造中增加表头参数

Question

我正在尝试调用一个API,它要求我传入一个API密钥。

我使用HttpURLConnection的服务调用工作正常。

url = new URL("https://developers.zomato.com/api/v2.1/search?entity_id=3&entity_type=city&q=" + params[0]);
        urlConnection = (HttpURLConnection) url.openConnection();

        urlConnection.setRequestProperty("user-key","9900a9720d31dfd5fdb4352700c");

        if (urlConnection.getResponseCode() != 200) {
            Toast.makeText(con, "url connection response not 200 | " + urlConnection.getResponseCode(), Toast.LENGTH_SHORT).show();
            Log.d("jamian", "url connection response not 200 | " + urlConnection.getResponseCode());
            throw new RuntimeException("Failed : HTTP error code : " + urlConnection.getResponseCode());
        }

然而，我不确定这是如何工作与改造，因为我的调用进入失败的所有时间。这是我在同一个服务调用中使用的代码

 @GET("search")
Call<String> getRestaurantsBySearch(@Query("entity_id") String entity_id, @Query("entity_type") String entity_type, @Query("q") String query,@Header("Accept") String accept, @Header("user-key") String userkey);

我用这个来称呼它

Call<String> call = endpoint.getRestaurantsBySearch("3","city","mumbai","application/json","9900a9720d31dfd5fdb4352700c");

所有这些调用都将进入改型中的OnFailure方法。如果不使用HeaderParameters发送它，它将以403获得成功，因为我显然需要在某个地方传递api键，但我不知道如何传递。

@GET("search")
Call<String> getRestaurantsBySearch(@Query("entity_id") String entity_id, @Query("entity_type") String entity_type, @Query("q") String query);

我在失败中遇到的错误是

java.lang.IllegalStateException: Expected a string but was BEGIN_OBJECT at line 1 column 2 path $

Answer 1

尝试使用此类型标头进行改装1.9和2.0。对于Json内容类型。

@Headers({"Accept: application/json"})
@POST("user/classes")
Call<playlist> addToPlaylist(@Body PlaylistParm parm);

您可以添加更多的头，例如

@Headers({
        "Accept: application/json",
        "User-Agent: Your-App-Name",
        "Cache-Control: max-age=640000"
    })

动态添加到标头：

@POST("user/classes")
Call<ResponseModel> addToPlaylist(@Header("Content-Type") String content_type, @Body RequestModel req);

调用您的方法即

mAPI.addToPlayList("application/json", playListParam);

或

每次都想通过然后用http拦截器创建HttpClient对象：

OkHttpClient httpClient = new OkHttpClient();
        httpClient.networkInterceptors().add(new Interceptor() {
            @Override
            public com.squareup.okhttp.Response intercept(Chain chain) throws IOException {
                Request.Builder requestBuilder = chain.request().newBuilder();
                requestBuilder.header("Content-Type", "application/json");
                return chain.proceed(requestBuilder.build());
            }
        });

然后添加到改装对象

Retrofit retrofit = new Retrofit.Builder().baseUrl(BASE_URL).client(httpClient).build();

更新如果您正在使用Kotlin删除{}否则将不起作用