为什么移除(x)不起作用？

Question

如果抛出的结果不是25头25尾（即24-26比），它应该擦除包含结果的列表my_list的内容，并再次循环50抛出，直到结果正好是25-25。

1. 打印空列表。
2. 启动while-loop，只有在my_list.count(1)为25时才结束。
3. 使用随机（1,2）掷硬币。
4. 将结果输入my_list。
5. 如果my_list.count(1)不完全是25，那么代码应该擦除列表的内容并重复while循环。

--编码：拉丁语-1-

import random
def coin_tosser():
    my_list = []

    # check if there is more or less 1 (heads) in the list
    # if there is more or less number ones in the list, loop
    # "while". If "coin tosser" throws exactly 25 heads and
    # 25 tails, then "while my_list.count(1) != 25:" turns True

    while my_list.count(1) != 25: # check if there is more or less 1 (heads) in the list
        print "Throwing heads and tails:"
        for i in range(50):
            toss = random.randint(int(1),int(2)) #tried this also without int() = (1,2)
            my_list.append(toss)
        if my_list.count(1) < 25 or my_list.count(1) > 25:
            my_list.remove(1) # remove number ones (heads) from the list
            my_list.remove(2) # remove number twos (tails) from the list

    # after loop is finished (25 number ones in the list), print following:

    print "Heads is in the list",
    print my_list.count(1), "times."
    print "Tails is in the list",
    print my_list.count(2), "times."
    # print
    print my_list

coin_tosser()

Answer 1

正如@Poke所说，list.remove(x)只删除list中x的首次出现。我只需在每次迭代中使用一个新的my_list列表，并去掉循环中的整个if。

while my_list.count(1) != 25: # check if there is more or less 1 (heads) in the list
    print "Throwing heads and tails:"
    my_list = []
    for i in range(50):
        toss = random.randint(int(1),int(2)) #tried this also without int() = (1,2)
        my_list.append(toss)

如果循环中有25个head，则不需要再次检查，因为您只是在循环条件while my_list.count(1)!=25中检查它

顺便说一句：

my_list.count(1) < 25 or my_list.count(1) > 25