如何使用RestTemplate在List中获取结果并将响应放入List？

Question

嗨，我想实现的是，我想使用其他API，并使用RestTemplate将一些响应数据放入函数中的List，下面是我的代码的样子：

@PostMapping("/save-new")
public ResponseEntity<ShipmentAddressGrouping> saveNewShipmentAddressGrouping(@Valid @RequestBody InputRequest<ShipmentAddressGroupingDto> request) {
    String url = baseUrl + "/load-list";

    HttpEntity<PartnerShipmentDto> requestPartnerShipmentDto = new HttpEntity<>(new PartnerShipmentDto());
    RestTemplate restTemplate = new RestTemplate();
    List<PartnerShipmentDto> partnerShipmentDto = restTemplate.postForObject(url, requestPartnerShipmentDto, new ParameterizedTypeReference<List<PartnerShipmentDto>>() {});

    ShipmentAddressGrouping newShipmentAddressGrouping = shipmentAddressGroupingService.save(request);
    return ResponseEntity.ok(newShipmentAddressGrouping);

}

如您所见，我尝试在List中获得响应，这是我在这里尝试的restTemplate。postForObject（url，requestPartnerShipmentDto，new ParameterizedTypeReference

但我在restTemplate中得到了带下划线的错误。如下所示的postForObject：

方法postForObject(字符串，对象，类，对象...)不适用于参数(String，HttpEntity，new ParameterizedTypeReference

我应该改变什么来解决这个问题？




Answer 1

如果要使用< code > ParameterizedTypeReference

List<PartnerShipmentDto> partnerShipmentDto = restTemplate.exchange(url, 
                HttpMethod.GET, 
                requestPartnerShipmentDto,
                new ParameterizedTypeReference<List<PartnerShipmentDto>>() {})
        .getBody();