为什么要获取org.hibernate.hql.internal.ast.QuerySyntaxException：需要连接的路径！连接3个表时

Question

我有三个实体基本信息，性别和部门。如果我加入了basicInfo和gender模型，那么它工作得很好，但是当我想加入department和其他两个实体时，就会显示

.QuerySyntaxException：需要连接的路径！

@Entity
@Table(name = "employeebasicinfo")
public class BasicInfoModel {
@Id private String employeeId;
@NotBlank private String firstName;
@NotBlank private String lastName;
@NotNull private Integer companyId;
@Transient private String companyName;
private String phoneNo;

@Column(name = "sex")
private char sexId;

@Transient private String sexName;

@Temporal(TemporalType.TIMESTAMP)
private Date birthDate;

@Temporal(TemporalType.TIMESTAMP)
private Date joiningDate;

@NotNull private Integer department;
@Transient private String departmentName;

@ManyToOne()
@JoinColumn(name = "sex", referencedColumnName = "id", insertable = false, updatable = false)
private GenderModel genderModel;

@ManyToOne
@JoinColumn(
  name = "department",
  referencedColumnName = "id",
  insertable = false,
  updatable = false)
private DepartmentModel departmentModel;
// getter setter
 }

 @Entity
 @Table(name = "gender")
 public class GenderModel implements Serializable {
 @Id
 @Column(name = "id")
 private char id;

 @Column(name = "name")
 private String name;
 //getter setter
}

   @Entity
   @Table(name = "department")
   public class DepartmentModel {
   @Id private int id;
   private String name;
   //getter setter
}

我的Dto类

public class BasicInfoDto {
  private String employeeId;
  private String firstName;
  private String lastName;
  private Integer companyId;
  private String companyName;
  private String phoneNo;
  private char sexId;
  private String sexName;
  private Date birthDate;
  private Date joiningDate;
  private Integer department;
  private String departmentName;


  public BasicInfoDto(char sexId, String sexName, int department, String departmentName) {
    this.sexId = sexId;
    this.sexName = sexName;
    this.department = department;
    this.departmentName = departmentName;

   //getter setter
  }

下面是我的存储库类：

@Repository
public interface BasicInfoRepository extends JpaRepository<BasicInfoModel, String> {


  @Query(
      value =
          "SELECT  new com.employeeAttendance.employeeAttendance.dto.BasicInfoDto ("
              + " a.sexId, b.name, a.department,c.name) FROM "
              + " BasicInfoModel a INNER JOIN GenderModel b on a.sexId = b.id" +
                   " INNER JOIN DepartmentMode c on a.department = c.id")
  List<BasicInfoDto> getBasicInfoList();
}

最后我得到了这个错误

Answer 1

您正在处理jpql中的实体属性，而不是表。所以您只告诉jpql使用哪个属性来加入：

"SELECT  new com.employeeAttendance.employeeAttendance.dto.BasicInfoDto ("
  + " a.sexId, b.name, a.department,c.name) FROM "
  + " BasicInfoModel a INNER JOIN a.genderModel b "
  + " INNER JOIN a.departmentModel c";