从字符串中删除特定的子字符串，并用数值将其拆分

Question

以下是我所做的：

var validArray = ["benson","basil","tiger","cocoa","pepper"];
var string = "benson prince 40, basil a 30, cocoa 40, tiger 30 and pepper asd 20";
var splitString = string.split(/\d+/g);
splitString = splitString.map(v => v.trim());
let realArray = [];
for(var i = 0; i < splitString.length - 1; i++){
    if(validArray.includes(splitString[i])){
        realArray.push(splitString[i]);
    }
}
console.log(realArray);

我得到一个空数组。如果我从字符串中删除“、”和“”，它将给我一个带有['cocoa'、'tiger']的数组，这是我想要的实际输出。

我想得到输出

['cocoa','tiger'] 

从绳子上

"benson prince 40, basil a 30, cocoa 40, tiger 30 and pepper asd 20".

请帮我想出一个解决办法。提前谢谢。

Answer 1

您可以创建单个模式一次，并捕获组中数字前面的单词。然后检查组值是否存在于validArray中

(\w+) \d+

正则表达式演示

例如

const validArray = ["benson", "basil", "tiger", "cocoa", "pepper"];
const realArray = [];
const regex = /(\w+) \d+/g;
const str = `benson prince 40, basil a 30, cocoa 40, tiger 30 and pepper asd 20`;
let m;
while ((m = regex.exec(str)) !== null) {
  if (validArray.includes(m[1])) realArray.push(m[1]);
}

console.log(realArray);

Answer 2

可以将逗号作为可选字符/\d添加到正则表达式中/g这个 表示0或其前面的一个字符。

js lang-js prettyprint-override">var validArray = ["benson","basil","tiger","cocoa","pepper"];
var string = "benson prince 40, basil a 30, cocoa 40, tiger 30 and pepper asd 20";
var splitString = string.split(/\d+,?/g);
splitString = splitString.map(v => v.trim());
let realArray = [];
for(var i = 0; i < splitString.length - 1; i++){
    if(validArray.includes(splitString[i])){
        realArray.push(splitString[i]);
    }
}
console.log(realArray);