Java Chess：检查棋手是否工作不正常的方法

Question

下面是我用Java编写的国际象棋游戏的粗略设置。主要有四个对象：

public boolean isInCheck(Player candidatePlayer) {

    String candidateColor = candidatePlayer.getColor();

    //get opposite color of candidatePlayer
    String oppositeColor = candidateColor.equals("w") ? "b" : "w";

    //loop through squares
    for (int i = 0; i < myBoard.length; i++) {
        for (int j = 0; j < myBoard[i].length; j++) {
            //if current square not empty
            if (! myBoard[i][j].isEmpty()) {
                //if piece at current square is opposite color of candidate player
                if (! myBoard[i][j].getPiece().getColor().equals(oppositeColor)) {
                    //if piece's current legal squares moves contains square of candidatePlayer's king
                    if (candidateColor.equals("w")) {
                        if (myBoard[i][j].getPiece().getLegalDestinationSquares(myBoard[i][j]).contains(whiteKingSquare)) {
                                return true;
                        }
                    } else {
                        if (myBoard[i][j].getPiece().getLegalDestinationSquares(myBoard[i][j]).contains(blackKingSquare)) {
                            return true;
                        }
                    }
                }   
            }
        }
    }
    return false;
}

谢谢！

Answer 1

我想你放错了！在

//if piece at current square is opposite color of candidate player
if (! myBoard[i][j].getPiece().getColor().equals(oppositeColor)) {

所以你实际上检查了候选人的颜色。将其更改为：

if (myBoard[i][j].getPiece().getColor().equals(oppositeColor)) {