将“{[/error]}”映射到公共org.springframework.http.ResponseEntity

Question

需要帮助请在MyBank jEE申请。问题是hibernate能够创建表，但它不能插入数据这里是我的代码

import java.util.Date;
import org.sid.dao.ClientRepository;
import org.sid.dao.CompteRepository;
import org.sid.entities.Client;
import org.sid.entities.Compte;
import org.sid.entities.CompteCourant;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.CommandLineRunner;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.context.ApplicationContext;

@SpringBootApplication
public class MyBankApplication implements CommandLineRunner {

    @Autowired
    private ClientRepository clientrepository;

    @Autowired
    private CompteRepository compteRepository;


    public static void main(String[] args) {
        ApplicationContext ctx = SpringApplication.run(MyBankApplication.class, args);
//      ClientRepository clientrepository = ctx.getBean(ClientRepository.class);
//      clientrepository.save(new Client("hassan", "[e-mail]"));
    }


    @Override
    public void run(String... arg0) throws Exception {
        Client c1 = clientrepository.save(new Client("Hassan", "[e-mail]"));
        Client c2 = clientrepository.save(new Client("Rachide", "[e-mail]"));
        Compte cpt = compteRepository.save(new CompteCourant("c1", new Date(), 90000, c1, 5000));
    }

}

package org.sid.dao;

import org.sid.entities.Client;
import org.springframework.data.jpa.repository.JpaRepository;

public interface ClientRepository extends JpaRepository<Client, Long> {

}

import java.io.Serializable;
import java.util.Collection;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.OneToMany;

@Entity
public class Client implements Serializable {
    @Id
    @GeneratedValue
    private Long code;
    private String nom;
    private String email;
    @OneToMany(mappedBy = "client", fetch = FetchType.LAZY)
    private Collection<Compte> comptes;

    public Client() {
        super();
    }

    public Client(String nom, String email) {
        super();
        this.nom = nom;
        this.email = email;
    }

    public Long getCode() {
        return code;
    }

    public void setCode(Long code) {
        this.code = code;
    }

    public String getNom() {
        return nom;
    }

    public void setNom(String nom) {
        this.nom = nom;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public Collection<Compte> getComptes() {
        return comptes;
    }

    public void setComptes(Collection<Compte> comptes) {
        this.comptes = comptes;
    }


}

以下是为什么它不能回答数据到数据库的错误

Answer 1

Hibernate：插入客户端（电子邮件，nom)值（？，？）Hibernate：插入客户端（电子邮件，nom)值（？，？）