整数的除法及其赋值[重复]

Question

可以理解的是：

  public int divide() {

  return 23/4; /* gives 5 , implicitly typecasting 5.75 to 5 ,due to 23 and 4 being
                  both integers ,at least I think this is */
  }

public double divide() {

  return 23.0/4.0; /*gives 5.75 , since it takes 23.0 and 4.0 to be float and not int*/

}

public double divide() {

  double intger = 23/4;
  return intger;

}

谢了。

我得到我的答案了。感谢所有帮助过的人。

Answer 1

23/4是一个int，然后将其隐式转换为double。

编辑：试试这个

System.out.println(23/4);
System.out.println((double)(23/4));
System.out.println((double)23/(double)4);