数组对象中的manipluate数据[重复]

Question

我希望循环通过一个对象，并对数据进行一些更改。我不是100%如果我实际上处理一个对象或一个数组包含多个对象，所以任何帮助都很感激。

下面是我的目标：

var screening = {
    source: "jacket",
    value: {
        Cyan: {
            dotshape: "C",
            frequency: 120,
            angle: 67.5
        },
        Magenta: {
            dotshape: "C",
            frequency: 120,
            angle: 37.5
        },
        Yellow: {
            dotshape: "C",
            frequency: 120,
            angle: 82.5
        },
        "PANTONE 3528 C": {
            dotshape: "C",
            frequency: 120,
            angle: 7.5
        },
        "PANTONE 293 C": {
            dotshape: "C",
            frequency: 120,
            angle: 7.5
        },
        "PANTONE 2748 C": {
            dotshape: "C",
            frequency: 120,
            angle: 7.5
        },
        Varnish: {
            dotshape: "C",
            frequency: 120,
            angle: 0
        }
    }
}

Old = [Cyan, Magenta, Yellow]
new = [changedName1, changedName2, changedName3]

提前致谢

Answer 1

使用delete删除旧属性，并使用[]（方括号表示法）和indexof获取旧属性并创建新属性：

js lang-js prettyprint-override">var screening = {
  source: "jacket",
  value: {
    Cyan: {
      dotshape: "C",
      frequency: 120,
      angle: 67.5
    },
    Magenta: {
      dotshape: "C",
      frequency: 120,
      angle: 37.5
    },
    Yellow: {
      dotshape: "C",
      frequency: 120,
      angle: 82.5
    },
    "PANTONE 3528 C": {
      dotshape: "C",
      frequency: 120,
      angle: 7.5
    },
    "PANTONE 293 C": {
      dotshape: "C",
      frequency: 120,
      angle: 7.5
    },
    "PANTONE 2748 C": {
      dotshape: "C",
      frequency: 120,
      angle: 7.5
    },
    Varnish: {
      dotshape: "C",
      frequency: 120,
      angle: 0
    }
  }
};

function oldToNew(oldNames, newNames) {
  Object.entries(screening.value).forEach(([key, prop]) => {
    if (oldNames.includes(key)) {
      screening.value[newNames[oldNames.indexOf(key)]] = screening.value[key];
      delete screening.value[key];
    }
  });
}

oldToNew(["Cyan", "Magenta", "Yellow"], ["Blue", "Purple", "Orange"]);

console.log(screening.value);