Mockito单元测试用例调用模棱两可（需要使其不模棱两可）

Question

我应该如何编写以下Mockito匹配器，以便调用不会有歧义？

我试图在代码中模拟的实际函数调用是：

//Variables
String url = http://theServer:8080/oath2-v1/token;
HttpEntity<String> request = new HttpEntity<String>("name=value",headers);

//Method call I am trying to mock using Mockito
response=cmsRestTemplate.exchange(url, HttpMethod.POST, request, DdsOAuthToken.class);

//From the Unit Test...
when(restTemplate.exchange(
    Matchers.anyString(),
    Matchers.any(HttpMethod.class),
    Matchers.any(HttpEntity.class),
    Matchers.<Class<DdsOAuthToken>>any(),
    Matchers.anyVararg()).thenReturn(response));

The method exchange(String, HttpMethod, HttpEntity<?>, Class<DdsOAuthToken>, Object[]) is ambiguous for the type RestTemplate

1. exchange(String url, HttpMethod method, HttpEntity<?> requestEntity, Class<T> responseType, Object... uriVariables)

2. exchange(String url, HttpMethod method, HttpEntity<?> requestEntity, ParameterizedTypeReference<T> responseType, Object... uriVariables)

Answer 1

必须向vararg参数添加强制转换(object[])。这可能与AnyVararg方法的声明有关。但我不确定。所以您的代码应该是：

//From the Unit Test...
when(restTemplate.exchange(
    Matchers.anyString(),
    Matchers.any(HttpMethod.class),
    Matchers.any(HttpEntity.class),
    Matchers.<Class<DdsOAuthToken>>any(),
    (Object[]) Matchers.anyVararg()).thenReturn(response));