从ArrayList中删除项

Question

我有一个数组列表假设列表，它有8个项目A-H，现在我想从列表中删除存储在int数组中的1,3,5位置项目。我该怎么做。

我正试着和你一起做这件事

ArrayList<String> list = new ArrayList<String>();
list.add("A");
list.add("B");
list.add("C");
list.add("D");
list.add("E");
list.add("F");
list.add("G");
list.add("H");

int i[] = {1,3,5};

for (int j = 0; j < i.length; j++) {
    list.remove(i[j]);
}

但在数组的第一个被删除的项被更改之后，在下一次迭代中它删除了错误的元素或给出异常。

Answer 1

 public void DeleteUserIMP(UserIMP useriamp) {
       synchronized (ListUserIMP) {
            if (ListUserIMP.isEmpty()) {
            System.out.println("user is empty");
        }  else {
            Iterator<UserIMP> it = ListUserIMP.iterator();
            while (it.hasNext()) {
                UserIMP user = it.next();
                if (useriamp.getMoblieNumber().equals(user.getMoblieNumber())) {
                    it.remove();
                    System.out.println("remove it");
                }
            }
            // ListUserIMP.remove(useriamp);

            System.out.println(" this user removed");
        }
        Constants.RESULT_FOR_REGISTRATION = Constants.MESSAGE_OK;
        // System.out.println("This user Deleted " + Constants.MESSAGE_OK);

    }
}

Answer 2

您可以使用ListIterator从ArrayList中删除元素，

ListIterator listIterator = List_Of_Array.listIterator();

 /* Use void remove() method of ListIterator to remove an element from List.
     It removes the last element returned by next or previous methods.
 */
listIterator.next();

//remove element returned by last next method
listIterator.remove();//remove element at 1st position
listIterator.next();
listIterator.next();
listIterator.remove();//remove element at 3rd position
listIterator.next();
listIterator.next();
listIterator.remove();//remove element at 5th position

Answer 3

在这种特定情况下，应按降序删除元素。首先索引5，然后索引3，然后索引1。这将从列表中删除元素，而不会产生不良的副作用。

for (int j = i.length-1; j >= 0; j--) {
    list.remove(i[j]);
}