如何将数组解析为Java中的对象

Question

我有一个作业要创建一个应用程序，当通过微调器选择学生的名字时，该应用程序会显示学生的名字和最终字母等级。我已经用名称设置了微调器，我已经从存储在资产中的文本文件中读取了名称和等级。我使用StringBuilder将该文件中的所有信息拆分为一个字符串数组。我想将这些数据解析成一个名为Student的对象，这样我就可以处理每个学生的成绩，但我不知道如何做到这一点。感谢您的帮助！

文本文件：

Name            Test1   Test2   Test3   Final
Adam    Anderson    81  90  85  87
Ben Brown       77  80  68  94
Chris   Cross       74  80  56  62
Don Dare        86  94  90  89
Eric    Earl        96  93  90  98
Fred    Foley       79  92  59  86
Gina    Gray        80  83  95  87
Holly   Hank        74  77  75  78
Ian Ingram      66  64  56  60
Jill    Johnson     90  98  78  89

到目前为止我的代码：

package lauren.ruff.lab4;

import android.content.res.AssetManager;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.AdapterView;
import android.widget.Spinner;
import android.widget.TextView;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.lang.StringBuilder;
import java.util.ArrayList;

public class MainActivity extends AppCompatActivity {

TextView name, grade;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    String strName;
    String strLastName;
    String strFirstName;
    String strFinalGrade;
    final String[] strSelected = new String[1];

    final int intTest1;
    int intTest2;
    int intTest3;
    int intFinal;
    int intFinalGrade;
    final int[] intSelection = new int[1];

    int intPointsPossible = 400;

    int finalGrades[] = new int[0];

    AssetManager am = getAssets();
    ArrayList<String> list = new ArrayList<String>();
    BufferedReader reader;
    StringBuilder sb = new StringBuilder();
    String[] tempList = new String[0];
    final ArrayList<Integer> finalList = new ArrayList<>();
    String line = " ";
    String item = " ";

    try {
        InputStream input = am.open("grades.txt");
        reader = new BufferedReader(new InputStreamReader(input));

        while (line != null){
            line = reader.readLine();
            list.add(line);

        }

        input.close();

        list.remove(0);

        for (int i = 0; i < list.size(); i++){
            sb.append(i);
        }

        tempList = sb.toString().split("\\s+");

        for (int j = 0; j < tempList.length; j++){
            finalList.add(j);
        }


    } catch (IOException e) {
        e.printStackTrace();
    }

    final Spinner spinner = (Spinner)findViewById(R.id.spName);

    spinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
        @Override
        public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l) {
            intSelection[0] = spinner.getSelectedItemPosition();
            strSelected[0] = spinner.getSelectedItem().toString();

            name = (TextView)findViewById(R.id.tvDisplayName);
            name.setText(strSelected[0]);

            grade = (TextView)findViewById(R.id.tvDisplayGrade);

            if (intSelection[0] == 0){
                int t1 = finalList.get(2);
                int t2 = finalList.get(3);
                int t3 = finalList.get(4);
                int t4 = finalList.get(5);
                Grades(t1,t2,t3,t4);
            }
        }

        @Override
        public void onNothingSelected(AdapterView<?> adapterView) {

        }
    });

}


public String Grades(int t1, int t2, int t3, int t4){
    int test1 = 0, test2 = 0, test3 = 0, finalScore = 0;
    double finalGrade;
    String letterGrade;
    finalGrade = (test1 + test2 + test3 + finalScore)/4;
    if (finalGrade > 93){
        letterGrade = "A";
    }
    else if (finalGrade > 88){
        letterGrade = "B+";
    }
    else if (finalGrade > 83){
        letterGrade = "B";
    }
    else if (finalGrade > 78){
        letterGrade = "C+";
    }
    else if (finalGrade > 73){
        letterGrade = "C";
    }
    else if (finalGrade > 65){
        letterGrade = "D";
    }
    else {
        letterGrade = "F";
    }

    return letterGrade;
}


}

Answer 1

您可以创建一个POJO（Plain java对象）类。

public class StudentPOJO{

   private String studentName;
   private String grade;


   public void setStudent(String studentName){
       this.studentName=studentName;
   }

   public void setStudentGrade(String grade){
       this.grade=grade;
   }

   public String getStudentGrade(){
       return grade;
   }

   public String getStudentName(){
       return studentName;
   }

}

通过这种方式，您可以为每个学生创建一个对象来存储他/她的信息。

Answer 2

拆分所有数据后，使用好的参数调用一个新Strudent（stringfirstname、stringlastname、int[]tests、int final）。

Answer 3

尝试读取txt文件并创建一个对象，而不是添加到列表中。试试这样的。

YourObject obj = new YourObject();
try
{
    List<String> yourLines = Files.readAllLines(java.nio.file.Paths.get("./grades.txt"), StandardCharsets.UTF_8);
    for (String line : yourLines) {
        String[] tokens = line.split(" ");
        obj.setName(tokens[0]);
    }
    System.out.println(obj.toString());
}
catch(IOException e)
{
    e.printStackTrace();
}`