将对象数组传递给构造函数[duplicate]

Question

我创建了一个Author对象，用于构造函数的方法签名:public Book[String name,Author Author1.......]但是，我所做的赋值要求将Author（实例变量）更改为Author[]。当然，现在我以前的构造函数不行了。这是密码

public class Author {
    private String name;
    private String email;
    private char gender;

    public String getName() {
        return name;
    }
    public void setEmail(String email){
        this.email = email;
    }
    public String getEmail(){
        return email;
    }
    public char getGender(){
        return gender;
    }

    public Author(String name, String email, char gender){
        this.name = name;
        this.email = email;
        this.gender = gender;
    }

    public String toString(){
        return "Author[name = " + this.name + ", email =  " + this.email + ", gender = " + this.gender + "]";
    }
}

public class Book {
    private String name;
    private Author[] author;
    private double price;
    private int quantity;

    // Getters and Setters
    public String getName(){
        return name;
    }
    public Author[] getAuthor(){
        return author;
    }
    public void setPrice(double price){
        this.price = price;
    }
    public double getPrice(){
        return price;
    }
    public void setQuantity(int quantity){
        this.quantity = quantity;
    }
    public int getQuantity(){
        return this.quantity;
    }



    // Constructors
    public Book(String name, Author[] author, int quantity){
        this.name = name;
        this.author = author;
        this.price = price;
    }

public class BookTest {
    public static void main(String[] args){
        Author author2 = new Author("Ben", "[e-mail]", 'm');
        Author author3 = new Author("Jennie", "[e-mail]", 'f');
        Book theIdiot = new Book("The Idiot", [author2, author3], 44.5, 33);
    }
}

如果我上传的方式不令人满意，我对任何不便表示歉意。我还没有学会使用堆栈溢出。
谢谢！

Answer 1

内联数组创建的语法为new arraytype[]{elem1,elemn2}

所以

Book theIdiot = new Book("The Idiot", new Author[]{author2, author3}, 44.5, 33);

或非内联版本

Author[] authors = new Author[2];
authors[0] = author2;
authors[1] = author3;
Book theIdiot = new Book("The Idiot", authors, 44.5, 33);

或者是评论中提到的“冰冻豌豆的罗迪”

Author[] authors = {author2, author3}
Book theIdiot = new Book("The Idiot", authors, 44.5, 33);