是否可以在父标记和子标记中编写XMLSchema-instance？

Question

我想创建下面的XML,它在“serviceaddrq”中具有xmlns:xsi=“http://www.w3.org/2001/xmlschema-instance”以及“service”标记。那么有没有可能创建这样的XML呢？

必需的XML：

<ServiceAddRQ echoToken="DummyEchoToken" version="2013/12"
  xmlns="http://www.test.com/schemas/2005/06/messages"
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.test.com/schemas/2005/06/messages ServiceAddRQ.xsd">  
        <Service xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="ServiceHotel" availToken="1jMqWGjqrx25Bp60gV2Qggb3">
        </Service>
</ServiceAddRQ>

Java生成的XML：在Java生成的代码中，我得到的是“服务”标记的空白XMLN。

<ServiceAddRQ xmlns="http://www.test.com/schemas/2005/06/messages"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" echoToken="6BB6B47EEEF4290515103925"
    version="2013/12"
    xsi:schemaLocation="http://www.test.com/schemas/2005/06/messages HotelValuedAvailRQ.xsd">   
    <Service xmlns="" xsi:type="ServiceHotel" availToken="1/YncBXZJXY17Z/ygNiO7gcg">        
    </Service>
</ServiceAddRQ>

相同的Java代码：

    static private Namespace NSSERVICE = Namespace.getNamespace("http://www.test.com/schemas/2005/06/messages");
    static private Namespace NSSCHEMA = Namespace.getNamespace("xsi", "http://www.w3.org/2001/XMLSchema-instance");

        String sXMLOut = "";
        Element barceloDS_requests= new Element("ServiceAddRQ",NSSERVICE);  
            barceloDS_requests.setAttribute("echoToken",searchParams.getSessionID().substring(0, 12)+GenTools.getSystemDateWithTime3());
            barceloDS_requests.setAttribute("version","2013/12");
            barceloDS_requests.addNamespaceDeclaration(NSSCHEMA);
            barceloDS_requests.setAttribute("schemaLocation", "http://www.test.com/schemas/2005/06/messages HotelValuedAvailRQ.xsd", NSSCHEMA);

         Namespace xsi = Namespace.getNamespace(GenTools.returnEmptyForNull(sXMLNS_XSI), "http://www.w3.org/2001/XMLSchema-instance");
         Element eleService=new Element("Service");
            eleService.setAttribute("type", "ServiceHotel", xsi);
            eleService.setAttribute("availToken",contractInfo[1]);
    barceloDS_requests.addContent(eleService);
    sXMLOut = new GetXMLOutputter().getXMLOutputter(barceloDS_requests,true);

Answer 1

序列化程序添加xmlns=“”是正确的，因为您创建了具有默认命名空间声明的顶级元素，但随后添加了不在命名空间中的子元素。要获得所需的输出，您需要创建service元素，其名称空间与根serviceaddrq相同http://www.test.com/schemas/2005/06/messages。像这样多试试：

static private Namespace NSSERVICE = Namespace.getNamespace("http://www.test.com/schemas/2005/06/messages");
static private Namespace NSSCHEMA = Namespace.getNamespace("xsi", "http://www.w3.org/2001/XMLSchema-instance");

String sXMLOut = "";
Element barceloDS_requests= new Element("ServiceAddRQ",NSSERVICE);  
barceloDS_requests.setAttribute("echoToken",searchParams.getSessionID().substring(0, 12)+GenTools.getSystemDateWithTime3());
barceloDS_requests.setAttribute("version","2013/12");
barceloDS_requests.addNamespaceDeclaration(NSSCHEMA);
barceloDS_requests.setAttribute("schemaLocation", "http://www.test.com/schemas/2005/06/messages HotelValuedAvailRQ.xsd", NSSCHEMA);

// --------------
// Key change -- Create Service element in the right namespace
Element eleService=new Element("Service",NSSERVICE);
// --------------

eleService.setAttribute("type", "ServiceHotel", NSSCHEMA);
eleService.setAttribute("availToken",contractInfo[1]);
barceloDS_requests.addContent(eleService);

这将创建以下内容的正确输出：

<ServiceAddRQ echoToken="DummyEchoToken" version="2013/12"
  xmlns="http://www.test.com/schemas/2005/06/messages"
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://www.test.com/schemas/2005/06/messages ServiceAddRQ.xsd">  
    <Service xsi:type="ServiceHotel" availToken="1jMqWGjqrx25Bp60gV2Qggb3"/>
</ServiceAddRQ>

service元素不需要它自己的xmlns:xsi声明，因为它是从父元素继承的，但是如果您特别想添加一个冗余的声明，那么可以使用eleService.AddNamespaceDeclaration(NSSCHEMA)但是不能保证，因为序列化器总是可以在不改变结果语义的情况下省略冗余的名称空间声明。