龙目岛@SuperBuilder抽象类，具有一般原因错误：不兼容的类型

Question

我有泛型类型的抽象类。它有抽象的toBuilder方法，如下所示:在抽象类上使用Lombok @SuperBuilder注释和toBuilder？

@Data
@SuperBuilder(toBuilder = true)
public abstract class TenantConfItem<T extends DeepCloneable<T>> {

    private final URN urn;

    private final Long version;

    private final T configData;

    public abstract TenantConfItemBuilder<T, ?, ?> toBuilder();

    public TenantConfItem<T> copy() {
        return this.toBuilder().build();
    }
}

子类型:

@SuperBuilder(toBuilder = true)
@EqualsAndHashCode(callSuper = true)
public class PointsExpirationByEarnedDatePolicy extends TenantConfItem<ExpirationByEarnedDate> implements Singleton {

}

这里我使用它的生成器:

val policyBuilder = PointsExpirationByEarnedDatePolicy.builder()
                .version(0L)
                .configData(new ExpirationByEarnedDate(retentionDays));

但是我收到配置数据的错误：

error: incompatible types: CAP#1 cannot be converted to ?
                .configData(new ExpirationByEarnedDate(retentionDays));
                           ^
  where CAP#1,CAP#2 are fresh type-variables:
    CAP#1 extends PointsExpirationByEarnedDatePolicyBuilder<CAP#2,CAP#1> from capture of ?
    CAP#2 extends PointsExpirationByEarnedDatePolicy from capture of ?

我猜这是因为父构建器有3个参数与泛型（tenantConfItemBuilder




Answer 1

匿名用户

< code > @ super builder(to builder = true)支持泛型类，并从子类中的超类细化类型参数。所以你的类和它们的注释是好的。

但是，lombok有时会在推断val的正确类型时遇到问题，尤其是在涉及类型参数时。

解决方案是用实际类型< code > pointsexpirationbyearnedtapolicybuilder替换< code>val