两个json属性java之间的条件[关闭]

Question

我想在对象使条件，例如，如果在响应我们有stateCode，选择属性stateCode，如果我们有stateName在响应选择stateName，它可能，你有解决方案吗？

这是对象的示例：

public class AdminAddressModel implements Serializable {

    @SerializedName("secondary")
    @ResponseRequiredField(canBeEmpty = true)
    @Expose
    private String secondary;

    @SerializedName("zipCode")
    @ResponseRequiredField(canBeEmpty = false)
    @Expose
    private String zipCode;

    @SerializedName("city")
    @ResponseRequiredField(canBeEmpty = false)
    @Expose
    private String city;

    @SerializedName("stateName")
    @ResponseRequiredField(canBeEmpty = false)
    @Expose
    private String stateName;

    @SerializedName("state")
    @ResponseRequiredField(canBeEmpty = false)
    @Expose
    private String state;

    @SerializedName("primary")
    @ResponseRequiredField(canBeEmpty = false)
    @Expose
    private String primary;

    public void setSecondary(String secondary){
        this.secondary = secondary;
    }

    public String getSecondary(){
        return secondary;
    }

    public void setZipCode(String zipCode){
        this.zipCode = zipCode;
    }

    public String getZipCode(){
        return zipCode;
    }

    public void setCity(String city){
        this.city = city;
    }

    public String getCity(){
        return city;
    }

    public void setStateName(String stateName){
        this.stateName = stateName;
    }

    public String getStateName(){
        return stateName;
    }

    public void setState(String state){
        this.state = state;
    }

    public String getState(){
        return state;
    }

    public void setPrimary(String primary){
        this.primary = primary;
    }

    public String getPrimary(){
        return primary;
    }

    @Override
    public String toString(){
        return
                "ShippingAddress{" +
                        "secondary = '" + secondary + '\'' +
                        ",zipCode = '" + zipCode + '\'' +
                        ",city = '" + city + '\'' +
                        ",stateName = '" + stateName + '\'' +
                        ",state = '" + state + '\'' +
                        ",primary = '" + primary + '\'' +
                        "}";
    }
}

这是stateCode，我想包括在那里，并作出条件，如果作为回应，我验证我们有stateCode，选择州代码，如果我们有stateName，选择stateName，有人帮助吗？

    @SerializedName("stateCode")
    @ResponseRequiredField(canBeEmpty = false)
    @Expose
    private String stateCode;

public void setStateCode(String stateCode){
    this.stateCode= stateCode;
}

public String getStateCode(){
    return stateCode;
}

此外，我还使用公共断言函数来验证我得到的对象模型和响应

AdminAddressModel不包含属性stateCode，响应中缺少必需字段stateName

我得到的响应，这就是为什么我想要这个条件，在响应stateCOde的EPs中，选择stateCode属性进行验证，如果他们有stateName，则选择stateName

Answer 1

由于目标是创造令人满意的条件，您可以涵盖以下4种可能性：

public void checkForStateCodeOrName() {

            if (stateCode != null && stateName != null) {
                // There's both stateCode and stateName
                return;
            }

            if (stateCode != null || stateName != null) {
                // at least one has value
                if (stateCode == null) {
                    // You got a stateName!

                } else {
                    // You got a stateCode
                }
            } else {
                // both are empty!
            }}