如何用PHP中的Regex匹配字符串中的任意单词

Question

我有这些线。我希望有一个正则表达式来匹配它们，并在将它们传递给preg_match函数时返回true。

do you want to eat katak at my hometown?
do you want to eat teloq at my hometown?
do you want to eat tempeyek at my hometown?
do you want to eat karipap at my hometown?

如何在正则表达式中创建与上述模式匹配的模式？像这样：

do you want to eat * at my hometown?

星号(*)表示任何单词。这是我目前掌握的正则表达式模式:

$text = "do you want to eat meatball at my hometown?";
$pattern = "/do you want to eat ([a-zA-Z0-9]) at my hometown?/i";

if (preg_match($pattern, $text)) {
    echo "A match was found.";
} else {
    echo "A match was not found.";
}

（[a-zA-Z0-9]） 格式在单词上不匹配。如何在单词上匹配字符串？

Answer 1

$text = "do you want to eat meatball at my hometown?";
$pattern = "/(\w+)(?=\sat)/";
if (preg_match($pattern, $text))

（\w）匹配一个或多个单词字符。

（？=\sat）是一个正前瞻，它匹配一个空格\s和处的字母。

正则表达式现场演示

Answer 2

使用量词:

$pattern = "/do you want to eat ([a-z0-9]*) at my hometown\?/i";
//                                here __^

并转义 ？ ==