分隔Java中的字母数字字符串[闭合]

Question

我有一个字符串，例如，AX3YM67。我想把字符串分离为Java中的A,X3,Y,M67。我怎么才能拿到这个？下面的代码是我尝试过的。

// Creating array of string length
char[] ch = new char[s.length()];

// Copy character by character into array
for (int i = 0; i < s.length(); i++) {
    ch[i] = s.charAt(i);
}

// finding all the indexes of elements
ArrayList<Integer> elementIndexes = new ArrayList<Integer>();

for (int j = 0; j < ch.length; j++) {
    if (Character.isLetter(ch[j])) {
        elementIndexes.add(j);
    }
}
for(int k = 0; k < elementIndexes.size(); k++) {
    if (elementIndexes.get(k) == elementIndexes.get(elementIndexes.size() - 1))  {
        terms.add(new Term(ch[elementIndexes.get(k)], Integer.parseInt(s.substring(elementIndexes.get(k) + 1))));
    }
    else if (elementIndexes.get(k) - elementIndexes.get(k + 1) == -1) {
        //System.out.println("K:" + k + " -- " + elementIndexes.get(k) + "-" + elementIndexes.get(k+1) + " = " + ch[k]);
        terms.add(new Term(ch[elementIndexes.get(k)], 1));
    } else {
        //System.out.println("G:" + elementIndexes.get(k) + "-" + formula.substring(elementIndexes.get(k), elementIndexes.get(k+1)));
        terms.add(new Term(ch[elementIndexes.get(k)], Integer.parseInt(s.substring(elementIndexes.get(k) + 1,elementIndexes.get(k+1)))));
    }
}

Answer 1

像这样试试。这将在前面没有数字的非数字之间的零宽度间隙上拆分。

String[] data = { "ABCDEF", "A1B2C3D4","AX3YM67", "A1233BB1233", "A3D456F6D" };
for (String str : data) {
    String st[] = str.split("(?!\\d)(?=\\D)");
    System.out.println(str + " --> " +  Arrays.toString(st));
}

印刷品

ABCDEF --> [A, B, C, D, E, F]
A1B2C3D4 --> [A1, B2, C3, D4]
AX3YM67 --> [A, X3, Y, M67]
A1233BB1233 --> [A1233, B, B1233]
A3D456F6D --> [A3, D456, F6, D]

Answer 2

public static String splitAlpha(String str){
    char first = str.charAt(0);
    StringBuilder sb = new StringBuilder();
    sb.append(first);
    for(int i = 1; i< str.length(); i++){
        char c = str.charAt(i);
        if(Character.isDigit(c)){
            sb.append(c);
         }else{
             sb.append(",").append(c);
         }
    }
        return sb.toString();
}