使用多个字符串分隔符拆分字符串

Question

如何将过滤器列表拆分为单个过滤器元件？split2String在线程“main”java.util.regex中导致：异常。PatternSyntaxException:索引10或（|和）附近的未闭合组(

public class TestIt {

    public static void main(String[] args) {
        // condition is Part of the Thunderbird Filter List
        String condition1 = "OR (subject,contains,Xxxx Yyyy) OR (subject,contains,Uuuu Cccc) AND (from,contains,Wwwww Zzzzz) OR (subject,contains,Uuuu Cccc)";
        String condition2 = "OR (subject,contains,Xxxx YyOR yy) OR (subject,contains,Uuuu CcAND cc) AND (from,contains,Wwwww Zzzzz) OR (subject,contains,Uuuu Cccc)";
        split1String(condition1);
        split1String(condition2);
        split2String(condition1);
        split2String(condition2);
        /*
         * Expected Result with condition2:
         * (subject,contains,Xxxx YyOR yy)
         * (subject,contains,Uuuu CcAND cc)
         * (from,contains,Wwwww Zzzzz)
         * (subject,contains,Uuuu Cccc)
         * 
         */
    }

    public static void split1String(String condition) {
        // Syntax=OK Result wrong
        String[] xsplitted = condition.split("OR |AND ");
        for (int i = 0; i < xsplitted.length; i++) {
            System.out.println(xsplitted[i]);
        }
    }

    public static void split2String(String condition) {
        // Syntax=NOT OK 
        String[] xsplitted = condition.split("OR (|AND (");
        for (int i = 0; i < xsplitted.length; i++) {
            System.out.println(xsplitted[i]);
        }
    }

Answer 1

您可以使用以下正则表达式来提取信息。因为所有你需要的都包含在括号里。

Pattern pattern = Pattern.compile("\\((.*?)\\)", Pattern.MULTILINE);

Matcher matcher = pattern.matcher(condition2);

while (matcher.find()) {
  for (int i = 1; i <= matcher.groupCount(); i++) {
    System.out.println(matcher.group(i));
  }
}

Answer 2

"OR（|AND（"这个正则表达式语法不正确。圆括号字符（在正则表达式中有特殊含义。它标志着捕获组的乞求。由于它是一个特殊字符，因此必须通过添加\\来转义：

"OR (subject,contains,Xxxx Yyyy) OR (subject,contains,Uuuu Cccc) AND (from,contains,Wwwww Zzzzz) OR (subject,contains,Uuuu Cccc)".split("OR \\(|AND \\(")

这给出了:

 String[5] { "", "subject,contains,Xxxx Yyyy) ", "subject,contains,Uuuu Cccc) ", "from,contains,Wwwww Zzzzz) ", "subject,contains,Uuuu Cccc)" }

因此，正确的正则表达式如下：＜code＞“或\（|和\（“）