循环检查播放器位置

Question

Player player = (Player) sender;
List< Player> prisoners = new ArrayList< Player>();
for (int i = 0; i < prisoners.size(); i++) {
    //loc(1-12) are coords in the form of a location variable. I just wanted to save some room.
    if (!(loc1 == prisoners.get(i))) {
        player.teleport(loc1);
    } else if (!(loc1 == prisoners.get(i).getLocation())) {
        player.teleport(loc2);
    } else if (!(loc2 == prisoners.get(i).getLocation())) {
        player.teleport(loc3);
    } else if (!(loc3 == prisoners.get(i).getLocation())) {
        player.teleport(loc4);
    } else if (!(loc4 == prisoners.get(i).getLocation())) {
        player.teleport(loc5);
    } else if (!(loc5 == prisoners.get(i).getLocation())) {
        player.teleport(loc6);
    } else if (!(loc6 == prisoners.get(i).getLocation())) {
        player.teleport(loc7);
    } else if (!(loc7 == prisoners.get(i).getLocation())) {
        player.teleport(loc8);
    } else if (!(loc8 == prisoners.get(i).getLocation())) {
        player.teleport(loc9);
    } else if (!(loc9 == prisoners.get(i).getLocation())) {
        player.teleport(loc10);
    } else if (!(loc10 == prisoners.get(i).getLocation())) {
        player.teleport(loc11);
    } else if (!(loc11 == prisoners.get(i).getLocation())) {
        player.teleport(loc12);
    } else {
        player.sendMessage("Sorry, the Prisoner's team is full. Try joining the Guards, or wait until the next round.");
        player.teleport(lobby);
        prisoners.remove(player);
    }

提前感谢！

Answer 1

这个条件

!(loc1 == prisoners.get(i))

将始终计算为true，因为loc1是一个坐标，而pronisers.get(i)是player对象。它们永远不会相等，所以您的上述条件计算为

!(false)  // meaning true

因此循环的每次迭代都将执行player.teleport(loc1)；