事件发生后如何使页面重定向到同一页面

Question

我正在努力使一个向上投票和向下投票的功能在我的网站。然而，有一个我不喜欢的特殊行为，那就是每当用户点击按钮时，他不应该被重定向到另一个页面，而应该保持在同一页面上。

点击upvote按钮后，会转到urlhttp://localhost:8001/upvote/2/，这是我不想要的。我希望它保持在同一页面上，即http://localhost:8001/view-supplore/

models.py

class User(AbstractBaseUser, PermissionsMixin):
    email = models.EmailField(max_length=254, unique=True)

    # CUSTOM USER FIELDS
    firstname = models.CharField(max_length=30)
    lastname = models.CharField(max_length=30)
    upvotes = models.IntegerField(default=0)
    downvotes = models.IntegerField(default=0)
    objects = UserManager()

    def get_absolute_url(self):
        return "/users/%i/" % (self.pk)
        
    def get_email(self):
        return self.email

views.py

def Viewsupplier(request):
    title = "All Suppliers"
    suppliers = User.objects.filter(user_type__is_supplier=True)

    context = {"suppliers":suppliers, "title":title}

    return render(request, 'core/view-suppliers.html', context)

@login_required
def upvote(request, pk):
    supplier_vote = get_object_or_404(User, id=pk)
    supplier_vote.upvotes += 1
    supplier_vote.save()
    upvote_count = supplier_vote.upvotes
    context = {"supplier_vote":supplier_vote, "upvote_count":upvote_count}
    return render(request, "core/view-suppliers.html", context)

@login_required
def downvote(request, pk):
    supplier_vote = get_object_or_404(User, id=pk)
    supplier_vote.downvotes -= 1
    supplier_vote.save()
    downvote_count = supplier_vote.downvotes
    context = {"supplier_vote":supplier_vote, "downvote_count":downvote_count}
    return render(request, "core/view-suppliers.html", context)

urls.py

from django.urls import path
from . import views

urlpatterns = [
    path('upvote/<int:pk>/', views.upvote, name='upvote'),
    path('downvote/<int:pk>/', views.downvote, name='downvote'),
]

查看-supplier.html

<table class="table table-borderless table-data3">
    <thead>
        <tr>
            <th>No</th>
            <th>Country</th>
            <th>Votes</th>
        </tr>
    </thead>
    <tbody>
        {% for supplier in suppliers %}
        <tr>
            <td>{{forloop.counter}}</td>
            <td>{{supplier.country}}</td>
            <td>
                <div class="table-data-feature">
                    <a href="{% url 'upvote' supplier.id %}" class="m-r-10">
                        <button class="item" data-toggle="tooltip" data-placement="top" title="Like">
                        <i class="zmdi zmdi-thumb-up"></i>{{upvote_count}}</button>
                    </a>
                    <a href="{% url 'downvote' supplier.id %}">
                        <button class="item" data-toggle="tooltip" data-placement="top" title="Dislike">
                        <i class="zmdi zmdi-thumb-down"></i>{{downvote_count}}</button>
                    </a>
                </div>
            </td>
        </tr>
        {% empty %}
            <tr><td class="text-center p-5" colspan="7"><h4>No supplier available</h4></td></tr>
        {% endfor %}
    </tbody>
</table>

Answer 1

您需要实现一个API（应用程序编程接口）来异步发送upvote和downvote。Django REST框架是创建您自己的API的方法。你可以在YouTube上看几个小时关于这个主题的视频教程。Django REST框架的文档非常好读。Django是一个服务器端的Web框架，这意味着只有当您提交给服务器时，它才能帮助您。您绝对可以重新加载相同的页面：

return HttpResponseRedirect(reverse('<app_name>:<url_name>'))

但是，会有一个中断。因此，处理这类行为的推荐方法是使用JavaScript的API（如REST框架的Fetch API）进行异步调用