我如何截图网站使用木偶并发送到消息discord.js？

Question

我想截图webiste和那个截图发送的消息不一致时，命令运行。我搞砸了，不知道该怎么办

const BaseCommand = require('../../utils/structures/BaseCommand');
const Discord = require("discord.js");
const fetch = require('node-fetch');
const cheerio = require("cheerio");
const puppeteer = require('puppeteer');


module.exports = class LinkCommand extends BaseCommand {
  constructor() {
    super('link', 'fun', []);
  }

  async run(client, message, args) {
    const browser = await puppeteer.launch();

    const page = await browser.newPage();
    await page.goto('https://www.hltv.org/team/5995/g2#tab-matchesBox');
    
    console.log(await page.content());
    await page.screenshot({path: 'screenshot.png'});
    
    await browser.close();
    
        message.channel.send(`${screenshot} je`)
    }
    
  }

Answer 1

如果您没有指定puppeteer的路径，映像将作为二进制数据（源）返回，可以直接发送（请参见DiscordJS'fileOptions):

let screenshot = await page.screenshot(); 
await browser.close();
message.channel.send("Screenshot", {files: [screenshot]});