无法获取反序列化后从xml文件返回的项目列表

Question

1. 列表项目

我从xml文件中转换并剥离了所有名称空间，并转换为Json对象，下面是我在jobject中的文件。这是我获取返回的Env对象的方法，但它返回了null。

你能帮忙指出我的模型中缺少了什么吗？我一直在做不同的路线都没有成功:(

 var jsonObject =
    JObject.Parse(Newtonsoft.Json.JsonConvert.SerializeXNode(XDocument.Parse(responseRet)));
                var Env= Newtonsoft.Json.JsonConvert.DeserializeObject<Envelope>(html" target="_blank">jsonObject.ToString());

     ```


  

这是我的班级:

公共类 SearchRecords_V2 { 公共列表

public class search txrecord _ V2 {[data member]public int search txrecordid { get；设置；} [DataMember]公共字符串FirstName { get设置；} [DataMember]公共字符串MiddleName { get设置；} [DataMember]公共字符串LastName { get设置；} [DataMember]公共字符串后缀{ get设置；} [DataMember]公共字符串SSN { get；设置；} [DataMember]公共字符串地址{ get设置；} [DataMember]公共字符串City { get设置；} [DataMember]公共字符串状态{ get设置；} [DataMember]公共字符串PostalCode { get设置；} [DataMember]公共字符串ComponentID { get设置；} [DataMember]公共字符串状态{ get设置；} [DataMember]公共字符串已创建{ get设置；} }

Answer 1

通过使用Newtonsoft.json库，您可以将其解析为点网模型

型号:

namespace ConvertFromJson
{
    public partial class DemoJsonObj
    {
        public Employees Employees { get; set; }
    }

    public partial class Employees
    {
        public List<Employee> Employee { get; set; }
    }

    public partial class Employee
    {
        public long Id { get; set; }
        public string FirstName { get; set; }
        public string LastName { get; set; }
        public Uri Photo { get; set; }
        public string SearchType { get; set; }
        public SearchRecords SearchRecords { get; set; }
    }

    public partial class SearchRecords
    {
        public List<SearchTestRecord> SearchTestRecord { get; set; }
    }

    public partial class SearchTestRecord
    {
        public long Field1 { get; set; }
        public string Field2 { get; set; }
        public RecordType RecordType { get; set; }
    }

    public partial class RecordType
    {
        public NativeRecordNumber NativeRecordNumber { get; set; }
    }

    public partial class NativeRecordNumber
    {
        public Uri Xmlns { get; set; }
        public string Text { get; set; }
    }
}

在你的代码里

var json = "{"employees":{"employee":[{"id":"1","firstName":"Tom","lastName":"Cruise","photo":"https://jsonformatter.org/img/tom-cruise.jpg","SearchType":"type1"},{"id":"2","firstName":"Maria","lastName":"Sharapova","photo":"https://jsonformatter.org/img/Maria-Sharapova.jpg","SearchType":"type1","SearchRecords":{"SearchTestRecord":[{"field1":"128181","field2":"TESTCASE","RecordType":{"NativeRecordNumber":{"@xmlns":"http://schemas.link.com/searchType/1.0.0/","#text":"MPXXXX2011"}}}]}},{"id":"3","firstName":"Robert","lastName":"Downey Jr.","photo":"https://jsonformatter.org/img/Robert-Downey-Jr.jpg","SearchType":"type2"}]}}"
DemoJsonObj obj = Newtonsoft.Json.JsonConvert.DeserializeObject<DemoJsonObj>(json);