就像Fizz buzz游戏。在特定数字中添加字符

Question

第一个字符打印在可被第一个[用户]输入的数字整除的任何数字旁边。

public static void main(String[] args){
    Scanner input = new Scanner(System.in);

    System.out.print("\nEnter 1st Number: ");
    int num = input.nextInt();

    System.out.print("\nEnter character: ");
    String c = input.nextLine();
    c = input.nextLine();

    System.out.print("\nEnter 2nd Number: ");
    int num1 = input.nextInt();

    System.out.print("\nEnter character: ");
    String c1 = input.nextLine();
    c1 = input.nextLine();

    int add = num+=num;

    for (int i = 1; i <= 10; i++){
    
        String s1 = String.valueOf(i);
        String s2 = c;
        String s3 = s1.concat(s2);
        String r1 = String.valueOf(i);
        String r2 = c1;
        String r3 = s1.concat(r2);

        System.out.println(i + s2 + r2);
    }
}

Answer 1

在for循环中，您需要检查i是否可以被num或num1整除，如果可以，则打印适当的字母。

方法nextline应在调用nextint之后和随后调用nextline之前调用。是否使用next（）或nextFoo（）后扫描器会跳过nextLine（）？

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);

    System.out.print("\nEnter 1st Number: ");
    int num = input.nextInt();
    input.nextLine();
    System.out.print("\nEnter character: ");
    String c = input.nextLine();

    System.out.print("\nEnter 2nd Number: ");
    int num1 = input.nextInt();
    input.nextLine();
    System.out.print("\nEnter character: ");
    String c1 = input.nextLine();
    for (int i = 1; i <= 10; i++) {
        System.out.print(i);
        if (i % num == 0) {
            System.out.print(c);
        }
        if (i % num1 == 0) {
            System.out.print(c1);
        }
        System.out.println();
    }
}

下面是上述代码的示例运行的输出。

Enter 1st Number: 2

Enter character: &

Enter 2nd Number: 3

Enter character: *
1
2&
3*
4&
5
6&*
7
8&
9*
10&

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);

    System.out.print("\nEnter 1st Number: ");
    int num = input.nextInt();
    input.nextLine();
    System.out.print("\nEnter character: ");
    String c = input.nextLine();

    System.out.print("\nEnter 2nd Number: ");
    int num1 = input.nextInt();
    input.nextLine();
    System.out.print("\nEnter character: ");
    String c1 = input.nextLine();
    String output;
    for (int i = 1; i <= 10; i++) {
        output = "" + i;
        if (i % num == 0) {
            output += c;
        }
        if (i % num1 == 0) {
            output += c1;
        }
        System.out.println(output);
    }
}