如何在android Studio中检测活动的互联网连接

Question

我的应用程序基于 Web 视图。我添加了带有重试按钮的布局，没有互联网活动。如果wifi或移动数据关闭，则应用程序显示带有重试按钮的布局。但是，如果在没有活动互联网连接的情况下连接wifi或移动数据，则它不会显示布局，而是显示错误页面。我应该怎么做才能检测活跃的互联网连接并克服这个问题？

我的代码:

public void internetcheck() {
    ConnectivityManager connectivityManager = (ConnectivityManager) this.getSystemService(Context.CONNECTIVITY_SERVICE);

    NetworkInfo mobiledata = connectivityManager.getNetworkInfo(connectivityManager.TYPE_MOBILE);
    NetworkInfo wifi = connectivityManager.getNetworkInfo(connectivityManager.TYPE_WIFI);

    
        if (mobiledata.isConnected()) {

            myWebView.setVisibility(View.VISIBLE);
            relativeLayout.setVisibility(View.GONE);
            mAdView.setVisibility(View.VISIBLE);
            myWebView.reload();


        } else if (wifi.isConnected()) {

            myWebView.setVisibility(View.VISIBLE);
            relativeLayout.setVisibility(View.GONE);
            mAdView.setVisibility(View.VISIBLE);
            myWebView.reload();

        } else {

            myWebView.setVisibility(View.GONE);
            relativeLayout.setVisibility(View.VISIBLE);
            mAdView.setVisibility(View.GONE);


        }


    }

Answer 1

添加此方法以检查是否有可用的internet连接-

public boolean isInternetAvailable() {
    try {
        InetAddress ipAddr = InetAddress.getByName("google.com"); 
        //You can replace it with your name
            return !ipAddr.equals("");

        } catch (Exception e) {
            return false;
    }
}

编辑

在Activity/Fragment中添加上述方法，如下所示-

在活动中

public class MainActivity extends AppCompatActivity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
       // you other code here
    }

    private boolean isInternetAvailable() {
    // past above methode body here
    }
}

您的interneteck（）方法将如下所示-

public void internetcheck() {
    ConnectivityManager connectivityManager = (ConnectivityManager) this.getSystemService(Context.CONNECTIVITY_SERVICE);

    NetworkInfo mobiledata = connectivityManager.getNetworkInfo(connectivityManager.TYPE_MOBILE);
    NetworkInfo wifi = connectivityManager.getNetworkInfo(connectivityManager.TYPE_WIFI);

    
        if (mobiledata.isConnected() || wifi.isConnected()) {
            if(isInternetAvailable()){
                myWebView.setVisibility(View.VISIBLE);
                relativeLayout.setVisibility(View.GONE);
                mAdView.setVisibility(View.VISIBLE);
                myWebView.reload();
            }
            //you can put another else in case there is no active internet
        } 
        else {
            myWebView.setVisibility(View.GONE);
            relativeLayout.setVisibility(View.VISIBLE);
            mAdView.setVisibility(View.GONE);
        }             
}

快乐编码！

Answer 2

使用 Utils 类 isInternetAvailable（） 函数获取设备的 Internet 状态。它自动支持已弃用的 isInternetAvailableLegacy（） 用法，适用于低于 Android M 的 Android 版本。

import android.annotation.SuppressLint
import android.content.Context
import android.net.ConnectivityManager
import android.net.NetworkCapabilities
import android.os.Build
import androidx.annotation.RequiresApi
class Utils constructor(context: Context,
                        private val logger: Logger) {

    enum class NETWORK_TYPE {
        WIFI,
        CELLULAR,
        ETHERNET
    }

    private val connectivityManager = context.getSystemService(Context.CONNECTIVITY_SERVICE) as ConnectivityManager

    @SuppressLint("MissingPermission")
    fun isInternetAvailable(): Boolean {
        return if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
            val transportType = getTransportType()
            if (transportType != null) true
            else isInternetAvailableLegacy()
        } else isInternetAvailableLegacy()
    }

    @Suppress("DEPRECATION")
    @SuppressLint("MissingPermission")
    private fun isInternetAvailableLegacy(): Boolean {
        try {
            val activeNetworkInfo = connectivityManager.activeNetworkInfo
            if (activeNetworkInfo != null && activeNetworkInfo.isConnected) {
                return true
            }
        } catch (e: Exception) {
            // TODO Handle Exception
        }
        return false
    }

    @RequiresApi(Build.VERSION_CODES.M)
    @SuppressLint("MissingPermission")
    private fun getTransportType(): NETWORK_TYPE? {
        val capabilities = connectivityManager.getNetworkCapabilities(connectivityManager.activeNetwork)
        capabilities?.let {
            return when {
                capabilities.hasTransport(NetworkCapabilities.TRANSPORT_CELLULAR) -> NETWORK_TYPE.CELLULAR
                capabilities.hasTransport(NetworkCapabilities.TRANSPORT_WIFI) -> NETWORK_TYPE.WIFI
                capabilities.hasTransport(NetworkCapabilities.TRANSPORT_ETHERNET) -> NETWORK_TYPE.ETHERNET
                else -> null
            }
        }
        return null
    }
}

Answer 3

也许是这个线程的副本。

似乎现在没有合适的方法来检查api的UI线程