在ViewPager android中创建片段

Question

MainActivity（扩展了fragmentActivity）有listview，它调用listviewadapter，其中有一个带有ViewpagerAdapter的ViewPager。现在，如果我需要在ViewPager中生成5个片段，如何将getFragmentManager（）传递给适配器。

MainActivity[fragmentActivity]---->Listview---->ListViewAdapter[自定义BaseAdapterAdapter与布局ViewPager的getview一起]-->ViewPager-->ViewPageAdapter[我需要根据位置创建5个片段？]

如果我粘贴整个代码，那么它会太长，所以我只附加了

public class ViewPagerAdapter extends PagerAdapter  {    
    ArrayList<ModelClass> arrayModelClasses = new ArrayList<ModelClass>();
    Context mcontext ;
    LinearLayout layouttest;

    final int PAGE_COUNT = 5;
    private String titles[] = new String[] { "Villa ","", "" ,"","",""};

    private int[] imageResId = { R.drawable.transparant,R.drawable.ic_action_place, R.drawable.icon_3d1,
            R.drawable.icon_flooplan,R.drawable.icon_gallery,R.drawable.icon_location };

    @SuppressLint("NewApi")
    @Override
    public void finishUpdate(ViewGroup container) {
        // TODO Auto-generated method stub
        super.finishUpdate(container);
    }

    public ViewPagerAdapter(ArrayList<ModelClass> arrayModelClasses , Context context) {
        super();
        this.arrayModelClasses = arrayModelClasses;
        this.mcontext= context;
    }

    @Override
    public boolean isViewFromObject(View collection, Object object) {
        return collection == ((View) object);
    }

    View view;

    @Override
    public Object instantiateItem(View collection, int position) {
        if (position == 0) {
            //need to call fragment 1
        }if (position == 1) {
        //need to call fragment 2
        }if (position == 2) {
        //need to call fragment 3
        }if (position == 3) {
        //need to call fragment 4
        }if (position == 4) {
        //need to call fragment 5
        }   
        return view;
    }

    @Override
    public void destroyItem(View container, int position, Object object) {
        ((ViewPager) container).removeView((View) object);
    }

    @Override
    public CharSequence getPageTitle(int position) {
         Drawable image = mcontext.getResources().getDrawable(imageResId[position]);
            image.setBounds(0, 0, image.getIntrinsicWidth(), image.getIntrinsicHeight());
            SpannableString sb = new SpannableString(" " +  titles[position] );
            ImageSpan imageSpan = new ImageSpan(image, ImageSpan.ALIGN_BOTTOM);
            sb.setSpan(imageSpan, 0, 1, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE);
            return sb;
    }

    @Override
    public int getCount() {
        return PAGE_COUNT;
    }

}

链接，但它使用FragmentPagerAdapter为viewPager并从FragmentActivity传递getSupportFragmentManager，但这是不可能的2个适配器，所以帮助。

Answer 1

考虑到您没有发布ListView适配器，我假设您扩展了BaseAdapter（无论哪种方式都是相似的）。在GetView(...)方法上，实例化一个新的ViewPagerAdapter并将其设置为列表项XML中定义的PagerAdapter。

注意：在listview中包含viewpager（特别是在以这种方式加载项时）可能会导致性能低下。