在Oracle中创建CTE

Question

我想创建一个CTE在Oracle不从现有的表中选择，而是具有插入到它的数据。当前，我正在创建一个表，然后在query完成后将其删除。有没有一种方法可以CTE有效地创建相同的对象？这是我当前的代码：

create table RTG_YEARS
(YR date);

insert into RTG_YEARS values (to_date('2013-01-01', 'yyyy-mm-dd'));
insert into RTG_YEARS values (to_date('2013-12-31', 'yyyy-mm-dd'));
insert into RTG_YEARS values (to_date('2014-01-01', 'yyyy-mm-dd'));
insert into RTG_YEARS values (to_date('2014-12-31', 'yyyy-mm-dd'));
insert into RTG_YEARS values (to_date('2015-01-01', 'yyyy-mm-dd'));
insert into RTG_YEARS values (to_date('2015-12-31', 'yyyy-mm-dd'));

Answer 1

您可以通过从对偶中选择日期值并将它们结合在一起来创建公用表表达式（CTE，子查询分解等）。

with RTG_YEARS (YR) as (
  select to_date('2013-01-01', 'yyyy-mm-dd') from dual
  union all select to_date('2013-12-31', 'yyyy-mm-dd') from dual
  union all select to_date('2014-01-01', 'yyyy-mm-dd') from dual
  union all select to_date('2014-12-31', 'yyyy-mm-dd') from dual
  union all select to_date('2015-01-01', 'yyyy-mm-dd') from dual
  union all select to_date('2015-12-31', 'yyyy-mm-dd') from dual
)
select * from RTG_YEARS;

YR       
----------
2013-01-01
2013-12-31
2014-01-01
2014-12-31
2015-01-01
2015-12-31

与CTE无关，但是您可以通过使用日期文字来减少输入：

with RTG_YEARS (YR) as (
  select date '2013-01-01' from dual
  union all select date '2013-12-31' from dual
  union all select date '2014-01-01' from dual
  union all select date '2014-12-31' from dual
  union all select date '2015-01-01' from dual
  union all select date '2015-12-31' from dual
)
select * from RTG_YEARS;