将输入字符串隐藏到interger中

Question

#This program calculates the average of integer entered
#Once the use press "S".
#"S" is the sentinel

COUNT= 0
SUM= 0
INT=1
Sentinel = "S"
print('Enter test scores as integers, or enter S to get average.')

INT=input('Enter integer: ')        # input received as a string to allow for the entry of "S"
#Continue processing as long as the user
#does not enter S
while INT!= Sentinel:
    INT=input('Enter integer: ')
    I=int(INT)                      #attempting to format the input(INT) as an integer
    COUNT= + 1
    SUM = COUNT + I
if INT == Sentinel:
    AVRG= SUM/(COUNT-1)

我不断得到这样的错误消息：Traceback（最近的调用为last）：文件“C:\users\joshu\documents\cop100python\practive examples\program4-13.py”，第16行，在I=INT(INT)valueerror中：INT（）的字面值为10:'s'

Answer 1

您的代码假设用户将始终输入一个数值。

这一行将接受用户输入的任何数据。它可以是数字或非数字。

INT=input('Enter integer: ')        # input received as a string to allow for the entry of "S"

在将数据转换为整数之前，请检查该值是否为数值。如果不是，那么您可能希望向用户发回一条错误消息。

I=int(INT)                      #attempting to format the input(INT) as an integer

if INT.isnumeric():
    I = int(INT)
else:
    print ('not a numeric value')

count = 0
total = 0
Sentinel = "S"

#Continue processing as long as the user does not enter S
while True:
    test_score = input('Enter test score as integer or enter S to get average: ')
    # input received as a string to allow for the entry of "S"
    
    if test_score.isnumeric():
        score = int(test_score)  #attempting to format the input(INT) as an integer
        count += 1
        total += score
    elif test_score.upper() == Sentinel:
        break
    else:
        print ('Not an integer or S. Please re-enter the value')
if count > 0:
    print (total, count)
    average_score = total/count
    print ('average score is : ', average_score)
else:
    print ('No valid entries were made. Average score is N/A')