多行字符串输入

Question

int main() {

char userInput[100];    //Store user input

//Take user input
//scanf(" %s",&userInput);
//scanf("%[^\n]s",&userInput);
//scanf("%[^\n]", &userInput);
//gets(userInput);
scanf("%[]s", &userInput); //This takes input but doesnt leave input loop

printf(" %s",userInput);

//i = index to start for looping through the string, starting at the beginning
//count = Stores occurrences of '$'
//inputLength = length of the input, used for limit of loop
int i =0,count =0;
int inputLength = strlen(userInput);

//Loop through the user input, if the character is '$', the integer count will be incremented
for (i; i < inputLength; i++){
    if (userInput[i] == '$'){
        count++;
    }
}

printf("%d", count);
return 0;
}

嗨，我的代码有一些问题，我需要接受一个3行的输入，并计算输入中“$”的数量。输入方法未注释为“scanf（”%[]s“,&userinput)；”是唯一一个我发现采取所有3行输入，但我不能打破输入循环继续我的程序。

任何帮助都将不胜感激

Answer 1

int readMatrix() {

char userInput[100][3];    //Store user input
int j = 0, m = 0;

for(m = 0; m < 3; m++){
    scanf("%s", &userInput[j][m]); //This takes input (Ex: 22 *(enter)* 33$ *(enter)* 66$ *(enter)*
    j++; //increase the column
}



int i =0,count =0;
m = 0;
//Loop through the user input, if the character is '$', the integer count will be incremented
for (i = 0; i < 100; i++){
    for(m = 0; m < 3; m++){
        if (userInput[i][m] == '$'){
            count++;
        }
    }
}
printf("%d", count);
return 0;
}