从qComboBox弹出菜单中捕捉按下鼠标按钮的信号

Question

我做了多选“QComboBox”。项目是可检查的（每个项目都有
复选框和文本值）。只有用户单击复选框时才会选中它。
我想要的是捕捉信号，当用户点击文本值，所以我可以设置
选中它旁边的复选框。怎么做？

以下是我如何将模型设置为组合框：

areas = ["Area one", "Area two", "Area three", "Area four"]
model = QtGui.QStandardItemModel(5, 1)# 5 rows, 1 col

firstItem = QtGui.QStandardItem("---- Select area(s) ----")
firstItem.setBackground(QtGui.QBrush(QtGui.QColor(200, 200, 200)))
firstItem.setSelectable(False)
model.setItem(0, 0, firstItem)

for i,area in enumerate(areas):
    item = QtGui.QStandardItem(area)
    item.setFlags(QtCore.Qt.ItemIsUserCheckable | QtCore.Qt.ItemIsEnabled)
    item.setData(QtCore.Qt.Unchecked, QtCore.Qt.CheckStateRole)
    model.setItem(i+1, 0, item)

self.ui.comboBox.setModel(model)        
self.ui.comboBox.installEventFilter(self)

I’ve added event filter to block wheel event,so firstItem‘s text is always
shown as “chosen”

def eventFilter(self,target,event):
    if target == self.ui.comboBox:
        if(event.type()== QtCore.QEvent.Wheel):
            #wheel event is blocked here
            return True
    return False

Answer 1

您需要将处理程序连接到pressedsignal梳子o’s
view:

    self.ui.comboBox.view().pressed.connect(self.handleItemPressed)
    ...

    def handleItemPressed(self, index):
        item = self.ui.comboBox.model().itemFromIndex(index)
        if item.checkState() == QtCore.Qt.Checked:
            item.setCheckState(QtCore.Qt.Unchecked)
        else:
            item.setCheckState(QtCore.Qt.Checked)