为什么我不能在React-router 4.x中嵌套Route组件？

Question

在世界上如何在react-router中使用嵌套路由，特别是版本4.x？以下在以前的版本中效果很好…

<Route path='/stuff' component={Stuff}>
  <Route path='/stuff/a' component={StuffA} />
</Route>

升级到4.x会引发以下警告…

警告：您不应在同一路径中使用 组件和 ；<路由子代>将被忽略

这到底是怎么回事？我已经搜索了几个小时的文档，但无法成功使嵌套路由正常工作。如何使用<Route> 组件 将其路由嵌套在react-router
v4中？我的简单示例如何转换为v4.x API遵从性以嵌套路由？

Answer 1

忘记您对React Router
<v4的了解。您通过逐字嵌套来嵌套路由<Routes>。检查此示例。具体检查主题组件。您无需预先声明路线，而是在渲染组件时动态声明路线。

import React from 'react'
import {
  BrowserRouter as Router,
  Route,
  Link
} from 'react-router-dom'

const BasicExample = () => (
  <Router>
    <div>
      <ul>
        <li><Link to="/">Home</Link></li>
        <li><Link to="/about">About</Link></li>
        <li><Link to="/topics">Topics</Link></li>
      </ul>

      <hr/>

      <Route exact path="/" component={Home}/>
      <Route path="/about" component={About}/>
      <Route path="/topics" component={Topics}/>
    </div>
  </Router>
)

const Home = () => (
  <div>
    <h2>Home</h2>
  </div>
)

const About = () => (
  <div>
    <h2>About</h2>
  </div>
)

const Topics = ({ match }) => (
  <div>
    <h2>Topics</h2>
    <ul>
      <li>
        <Link to={`${match.url}/rendering`}>
          Rendering with React
        </Link>
      </li>
      <li>
        <Link to={`${match.url}/components`}>
          Components
        </Link>
      </li>
      <li>
        <Link to={`${match.url}/props-v-state`}>
          Props v. State
        </Link>
      </li>
    </ul>

    {/* NESTED ROUTES */}
    <Route path={`${match.url}/:topicId`} component={Topic}/>
    <Route exact path={match.url} render={() => (
      <h3>Please select a topic.</h3>
    )}/>
  </div>
)

const Topic = ({ match }) => (
  <div>
    <h3>{match.params.topicId}</h3>
  </div>
)

export default BasicExample