odoo-2个字段的many2one字段组合的显示名称

Question

在我的模块中，我有以下many2one字段： 'xx_insurance_type': fields.many2one('xx.insurance.type', string='Insurance')

在xx.insurance.type以下位置：

class InsuranceType(osv.Model):
    _name='xx.insurance.type'

    _columns = {
        'name' : fields.char(size=128, string = 'Name'),
        'sale_ids': fields.one2many('sale.order', 'xx_insurance_type', string = 'Sale orders'),
        'insurance_percentage' : fields.float('Insurance cost in %')
    }

我知道many2one场取 名字 字段的显示名称，但我想有它使用的组合name，并insurance_percentage在形式name + " - " + insurance_percentage + "%"

我读过最好覆盖该get_name方法，所以我尝试了以下方法：

def get_name(self,cr, uid, ids, context=None):
    if context is None:
        context = {}
    if isinstance(ids, (int, long)):
        ids = [ids]

    res = []
    for record in self.browse(cr, uid, ids, context=context):
         name = record.name
         percentage = record.insurance_percentage
         res.append(record.id, name + " - " + percentage + "%")
    return res

并将其放在ÌnsuranceType`类中。既然什么也没发生：我是否必须将其放置在包含该字段的主类中？如果是这样，是否还有其他方法可以执行此操作，因为这也可能会更改其他many2one字段的显示方式？

Answer 1

如果您不想更改many2one与模型相关的其余部分的显示名称，则xx.insurance.type可以在XML视图中向many2one要修改其显示名称的上下文中添加一个上下文：

<field name="xx_insurance_type" context="{'special_display_name': True}"/>

然后，在您的name_get函数中：

def name_get(self, cr, uid, ids, context=None):
    if context is None:
        context = {}
    if isinstance(ids, (int, long)):
        ids = [ids]
    res = []
    if context.get('special_display_name', False):
        for record in self.browse(cr, uid, ids, context=context):
            name = record.name
            percentage = record.insurance_percentage
            res.append(record.id, name + " - " + percentage + "%")
    else:
        # Do a for and set here the standard display name, for example if the standard display name were name, you should do the next for
        for record in self.browse(cr, uid, ids, context=context):
            res.append(record.id, record.name)
    return res