如何删除类方法中的try / catch重复项？

Question

我有RESTeasy服务。并已对使用的方法实施了简单的错误处理，try catch并且感觉不太好。我注意到我的所有方法都尝试重复捕获。所以我想问问如何避免重复（以减少代码大小）try catch但又不会丢失功能。

@Path("/rest")
@Logged
@Produces("application/json")
public class CounterRestService {

  @POST
  @Path("/create")
  public CounterResponce create(@QueryParam("name") String name) {
    try {
        CounterService.getInstance().put(name);
        return new CounterResponce();
    } catch (Exception e){
        return new CounterResponce("error", e.getMessage());
    }   
}

@POST
@Path("/insert")
public CounterResponce create(Counter counter) {
    try {
        CounterService.getInstance().put(counter);
        return new CounterResponce();
    } catch (Exception e){
        return new CounterResponce("error", e.getMessage());
    }
}

@DELETE
@Path("/delete")
public CounterResponce delete(@QueryParam("name") String name) {
    try {
        CounterService.getInstance().remove(name);
        return new CounterResponce();
    } catch (Exception e){
        return new CounterResponce("error", e.getMessage());
    }
}
... // other methods with some try catch pattern

响应

public class CounterResponce {
private String status;

@JsonSerialize(include=Inclusion.NON_NULL)
private Object data;

public CounterResponce() {
    this.status = "ok";
}

public CounterResponce(Object o) {
    this.status = "ok";
    this.data = o;
}

public CounterResponce(String status, Object o){
    this.status = status;
    this.data = o;
}

public String getStatus() {
    return status;
}
public void setStatus(String status) {
    this.status = status;
}
public Object getData() {
    return data;
}
public void setData(Object data) {
    this.data = data;
}
}

异常源

public class CounterService {

private Map<String, StatisticCounter> counters = new HashMap<String, StatisticCounter>();

private static CounterService instance = null;

protected CounterService() {}

public static CounterService getInstance() {
      if(instance == null) {
         instance = new CounterService();
      }
      return instance;
}

public StatisticCounter get(String name){
    StatisticCounter c =  counters.get(name);
    if(c == null)throw new IllegalArgumentException("Counter "+name+" not exist");
    return c;
}

public void put(String name){
    if(name==null)throw new IllegalArgumentException("null can`t be as name");
    if(counters.get(name)!=null)throw new IllegalArgumentException("Counter "+name+" exist");
    counters.put(name, new Counter(name));
 }...

Answer 1

您问题中的评论为您指明了正确的方向。由于答案未提及，因此我将在此答案中概述一般思想。

延伸 WebApplicationException

JAX-
RS允许定义Java异常到HTTP错误响应的直接映射。通过扩展WebApplicationException，您可以创建特定于应用程序的异常，这些异常将使用状态码和可选消息作为响应的主体来构建HTTP响应。

以下异常生成404状态代码为HTTP的响应：

public class CustomerNotFoundException extends WebApplicationException {

    /**
    * Create a HTTP 404 (Not Found) exception.
    */
    public CustomerNotFoundException() {
      super(Responses.notFound().build());
    }

    /**
    * Create a HTTP 404 (Not Found) exception.
    * @param message the String that is the entity of the 404 response.
    */
    public CustomerNotFoundException(String message) {
      super(Response.status(Responses.NOT_FOUND).
      entity(message).type("text/plain").build());
    }
}

WebApplicationException是a
RuntimeException，不需要将其包装在try-
catch块中或在throws子句中声明：

@Path("customers/{customerId}")
public Customer findCustomer(@PathParam("customerId") Long customerId) {
    Customer customer = customerService.find(customerId);
    if (customer == null) {
        throw new CustomerNotFoundException("Customer not found with ID " + customerId);
    }
    return customer;
}

创建ExceptionMappers

在其他情况下，抛出WebApplicationException或扩展类的实例可能不合适WebApplicationException，而是将现有异常映射到响应可能更可取。

在这种情况下，可以使用自定义异常映射提供程序。提供者必须实现该ExceptionMapper<E extends Throwable>接口。例如，以下将JAP映射EntityNotFoundException到HTTP
404响应：

@Provider
public class EntityNotFoundExceptionMapper 
    implements ExceptionMapper<EntityNotFoundException> {

    @Override
    public Response toResponse(EntityNotFoundException ex) {
      return Response.status(404).entity(ex.getMessage()).type("text/plain").build();
    }
}

EntityNotFoundException引发an时，实例的toResponse(E)方法EntityNotFoundExceptionMapper将被调用。

该@Provider注解声明了类是感兴趣的JAX-
RS运行。可以将该类添加到Application配置的实例的类集中。