Browserify无法使用babelify转换创建捆绑包（TypeError：路径必须为字符串。）

Question

我已经编写了一个吞吞吐吐的任务，使用watchify和babelify作为转换将.jsx和.js脚本编译为一个包。由于某种原因，我的gulp脚本似乎在转换中令人窒息，而且我不确定为什么：

gulp.task('browserify', function() {
  var bundle = watchify(browserify('./app/jsx/client/index.jsx', {
    extensions: ['.js', '.jsx'],
    debug: process.env.NODE_ENV === 'development'
  }));
  bundle.transform(babelify);
  bundle.on('update', function() {
    rebundle(bundle);
  });


  function rebundle(bundle) {
    return bundle.bundle()
    .on('error', function(error) {
      console.log(error.stack, error.message);
      this.emit('end');
    })
    .pipe(
        gulpif(
          (process.env.NODE_ENV == 'production'),
          require('gulp-rename')('bundle.min.js'),
          require('gulp-rename')('bundle.js')
        )
    )
    .pipe(gulpif((process.env.NODE_ENV == 'production'), buffer()))
    .pipe(gulpif((process.env.NODE_ENV == 'production'), uglify()))
    .pipe(gulp.dest('dist/js'));
  }

  return rebundle(bundle);
});

在控制台中…

path.js:8
    throw new TypeError('Path must be a string. Received ' +
    ^

TypeError: Path must be a string. Received undefined
    at assertPath (path.js:8:11)
    at Object.posix.join (path.js:480:5)
    at Transform.stream._transform (/home/zipp/search-admin/node_modules/gulp-rename/index.js:52:22)
    at Transform._read (_stream_transform.js:167:10)
    at Transform._write (_stream_transform.js:155:12)
    at doWrite (_stream_writable.js:292:12)
    at writeOrBuffer (_stream_writable.js:278:5)
    at Transform.Writable.write (_stream_writable.js:207:11)
    at Readable.ondata (/home/zipp/search-admin/node_modules/browserify/node_modules/read-only-stream/node_modules/readable-stream/lib/_stream_readable.js:572:20)
    at emitOne (events.js:77:13)
    at Readable.emit (events.js:169:7)

Answer 1

该错误是因为您需要vinyl-source-stream在那里。结果.bundle()是文件数据的标准Node流。您正在获取数据，并将其传递给它，rename这将需要Gulp
File对象流。

var source = require('vinyl-source-stream');

// stuff

  function rebundle(bundle) {
    return bundle.bundle()
    .on('error', function(error) {
      console.log(error.stack, error.message);
      this.emit('end');
    })
    .pipe(
        gulpif(
          (process.env.NODE_ENV == 'production'),

          // Use 'source' here instead, which converts binary
          // streams to file streams.
          source('bundle.min.js'),
          source('bundle.js')
        )
    )
    .pipe(gulpif((process.env.NODE_ENV == 'production'), buffer()))
    .pipe(gulpif((process.env.NODE_ENV == 'production'), uglify()))
    .pipe(gulp.dest('dist/js'));
  }

rename可以使用而不是使用source来定义文件的初始名称。