正则表达式回溯直到Java溢出

Question

下面的表达式：

^(#ifdef FEATURE)+?\s*$((\r\n.*?)*^(#endif)+\s*[\/\/]*\s*(end of)*\s*FEATURE)+?$

运行编译的.Jar文件时，覆盖匹配的缓冲区。

匹配的字符串可以类似于：

这是一条垃圾线

#ifdef FEATURE
#endif // FEATURE的结尾

这是一条垃圾线

#ifdef功能

这是一条应该匹配的垃圾线：HOLasduiqwhei＆//功能fjfefj #endif // h

#endif功能

这是一条垃圾线

因此，粗体字符串应匹配。错误如下：

   at java.util.regex.Pattern$GroupHead.match(Unknown Source)
   at java.util.regex.Pattern$Loop.match(Unknown Source)
   at java.util.regex.Pattern$GroupTail.match(Unknown Source)
   at java.util.regex.Pattern$Curly.match1(Unknown Source)
   at java.util.regex.Pattern$Curly.match(Unknown Source)
   at java.util.regex.Pattern$Slice.match(Unknown Source)
   at java.util.regex.Pattern$GroupHead.match(Unknown Source)
   at java.util.regex.Pattern$Loop.match(Unknown Source)
   at java.util.regex.Pattern$GroupTail.match(Unknown Source)
   at java.util.regex.Pattern$Curly.match1(Unknown Source)
   at java.util.regex.Pattern$Curly.match(Unknown Source)
   at java.util.regex.Pattern$Slice.match(Unknown Source)
   at java.util.regex.Pattern$GroupHead.match(Unknown Source)
   at java.util.regex.Pattern$Loop.match(Unknown Source)
   at java.util.regex.Pattern$GroupTail.match(Unknown Source)
   at java.util.regex.Pattern$Curly.match1(Unknown Source)
   at java.util.regex.Pattern$Curly.match(Unknown Source)
   at java.util.regex.Pattern$Slice.match(Unknown Source)
   at java.util.regex.Pattern$GroupHead.match(Unknown Source)
   at java.util.regex.Pattern$Loop.match(Unknown Source)
   at java.util.regex.Pattern$GroupTail.match(Unknown Source)
   at java.util.regex.Pattern$Curly.match1(Unknown Source)
   at java.util.regex.Pattern$Curly.match(Unknown Source)
   at java.util.regex.Pattern$Slice.match(Unknown Source)
   at java.util.regex.Pattern$GroupHead.match(Unknown Source)
   at java.util.regex.Pattern$Loop.match(Unknown Source)
   at java.util.regex.Pattern$GroupTail.match(Unknown Source)
   at java.util.regex.Pattern$Curly.match1(Unknown Source)
   at java.util.regex.Pattern$Curly.match(Unknown Source)
   at java.util.regex.Pattern$Slice.match(Unknown Source)

欢迎采取任何回避策略或改进表达方式的方法。(?>)由于某些原因，我尝试了原子组，但并未简化。

代码如下：

公共字符串带（字符串文本）{

    ArrayList<String> patterns=new ArrayList<String>();
    patterns=readFile("Disabled_Features.txt");
    for(int i = 0; i < patterns.size(); ++i)
    {

      Pattern todoPattern = Pattern.compile("^#ifdef "+patterns.get(i)+"((?:\\r?\\n(?!#endif (?:// end of )?"+patterns.get(i)+"$).*)*)\\r?\\n#endif (?:// end of )?"+patterns.get(i)+"$",Pattern.MULTILINE);

      Matcher m = todoPattern.matcher(text);
      text = m.replaceAll("");
    }
    return text;        
}

Answer 1

我尝试了@Wiktor编写的代码，效果很好

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class TestRegex {
  public static void main(String[] args) {
    String text = "this is a junk line\n" + 
        "\n" + 
        "#ifdef FEATURE \n" + 
        "#endif // end of FEATURE\n" + 
        "\n" + 
        "this is a junk line\n" + 
        "\n" + 
        "#ifdef FEATURE\n" + 
        "\n" + 
        "this is a junk line that should be matched: HOLasduiqwhei & // FEATURE fjfefj #endif // h\n" + 
        "\n" + 
        "#endif FEATURE\n" + 
        "\n" + 
        "this is a junk line";

    // this version does not use Pattern.MULTILINE, this should reduce the backtraking
    Matcher matcher2 = Pattern.compile("\\n#ifdef FEATURE((?:\\r?\\n(?!#endif (?:// end of )?FEATURE).*)*)\\r?\\n#endif (?:// end of )?FEATURE").matcher(text);
    while (matcher2.find()) {
      System.out.println(matcher2.group());
    }

  }
}

这让我认为您的问题是由于输入文件的大小所致。

因此，如果文件太大，则可以将输入实现为CharSequence，从而可以包装大文本文件。为什么？因为Matcher从a 构建a
Pattern需要一个CharSequence参数。

https://github.com/fge/largetext