XPath-如何获取具有相同名称的多个标签的列表

Question

<?xml version="1.0"?>
<shop>
    <shoes>
        <brand>Nike</brand>
        <size>13</size>
        <colour>White</colour>
        <price>34.99</price>
        <additional name="abc">123</additional>
        <additional name="def">456</additional>
        <additional name="ghi">789</additional>
        <additional name="jkl">101</additional>
    </shoes>
    <trousers>
        <brand>Levi</brand>
        <size>36</size>
        <legSize>33</legSize>
        <colour>Stonewash</colour>
        <price>69.99</price>
        <additional name="mno">112</additional>
        <additional name="pqr">131</additional>
        <additional name="stu">415</additional>
        <additional name="vwx">161</additional>
    </trousers>
</shop>

给定上面的xml文件，我将如何检索<additional>标签内所有标签的列表<shoes>？我想获取“名称”的所有值以及标签之间的数字值。像这样：

abc, 123
def, 456
ghi, 789
jkl, 101

问题是我不知道会有多少个附加标签。可能没有，也可能有20。我需要某种方法来对它们全部进行计数，然后删除信息。

Answer 1

这是一个使用XPathJDK执行查询的示例。它假定变量xml包含您的XML文档。

XPathFactory factory = XPathFactory.newInstance();
XPath xPath = factory.newXPath();
NodeList nodeList = (NodeList) xPath.evaluate("//shoes/additional", new InputSource(new StringReader(xml)), XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); ++i) {
    String name = nodeList.item(i).getAttributes().getNamedItem("name").getNodeValue();
    String text = nodeList.item(i).getTextContent();
    System.out.println(name + ", " + text);
}