解析SAS宏中的JSON对象

Question

这是输入的JSON文件。它必须在SAS数据集中解析。

"results":
[
 {
    "acct_nbr": 1234,
    "firstName": "John",
    "lastName": "Smith",
    "age": 25,
    "address": {
        "streetAddress": "21 2nd Street",
        "city": "New York",
        "state": "NY",
        "postalCode": "10021"
        }
 }
,
{
    "acct_nbr": 3456,
    "firstName": "Sam",
    "lastName": "Jones",
    "age": 32,
    "address": {
        "streetAddress": "25 2nd Street",
        "city": "New Jersy",
        "state": "NJ",
        "postalCode": "10081"
        }
 }
]

我想要这样的SAS数据集中仅Address字段的输出：

ACCT_NBR    FIELD_NAME  FIELD_VALUE
1234    streetAddress   21 2nd Street
1234    city    New York
1234    state   NY
1234    postalCode  10021
3456    streetAddress   25 2nd Street
3456    city    New Jersy
3456    state   NJ
3456    postalCode  10081

我尝试了单独的方式，但没有类似的输出。甚至尝试过从PDF进行扫描…但无法获得所需的输出…

这是我的代码…和输出…

LIBNAME src  '/home/user/read_JSON';

filename data '/home/user/read_JSON/test2.json';
data src.testdata2;
    infile data lrecl = 32000 truncover scanover;
        input @'"streetAddress": "' streetAddress $255. @'"city": "' city $255. @'"state": "' state $2. @'"postalCode": "' postalCode $255.;
        streetAddress = substr(streetAddress,1,index(streetAddress,'",')-2);
        city = substr( city,1,index( city,'",')-2);
        state = substr(state,1,index(state,'",')-2);
        postalCode = substr(postalCode,1,index(postalCode,'",')-2);
run;

proc print data=src.testdata2;
RUN;

我 在.lst文件中的 输出

The SAS System   09:44 Tuesday, January 14, 2014   1
           street                            postal
 Obs      Address         city      state     Code

  1     21 2nd Stree    New Yor       NY      10021"
  2     25 2nd Stree    New Jers      NJ      10081"

Answer 1

要使用仅SAS的解决方案来回答您的问题，您有两个问题：

• 使用SCAN而不是substr获取未逗号/引号部分
• acct_nbr 是数字，因此您需要从输入中删除最后的引号。

这是正确的代码（我更改了目录，您需要将其改回）：

filename data 'c:\temp\json.txt';
data testdata2;
    infile data lrecl = 32000 truncover scanover;
        input 
            @'"acct_nbr": ' acct_nbr $255.
            @'"streetAddress": "' streetAddress $255. 
            @'"city": "' city $255. 
            @'"state": "' state $2. 
            @'"postalCode": "' postalCode $255.;

        acct_nbr=scan(acct_nbr,1,',"');
        streetAddress = scan(streetAddress,1,',"');
        city = scan(city,1,',"');
        state = scan(state,1,',"');
        postalCode = scan(postalCode,1,',"');
run;

proc print data=testdata2;
RUN;