通过嵌套json为python中的特定键进行递归迭代

Question

我正在尝试从json文件中提取嵌套值。我想打印出每个“

id”键的每个值。我想我已经接近了，但无法弄清楚为什么obj类型从字典更改为列表，然后为什么我无法解析该列表。这是我正在使用的json的链接： http

//hastebin.com/ratevimixa.tex

这是我当前的代码：

#!/usr/bin/env python
#-*- coding: utf-8 -*-

import json

json_data = open('JubJubProductions.json', 'r+')
jdata = json.loads(json_data.read().decode("utf-8"))

def recursion(dict):

    for key, value in dict.items():

        if type(value) == type(dict):
            if key != "paging":
                for key, value in value.items():
                    if isinstance (value,list):
                        print key
                        # place where I need to enter list comprehension?
                if type(value) == type(dict):
                    if key == "id":
                        print " id found " + value
                    if key != "id":
                        print key + " 1st level"
                if key == "id":
                    print key
        else:
            if key == "id":
                print "id found " + value       
if __name__ == '__main__':
    recursion(jdata)

--------------------------------------------------

----------------------------------------- 更新

现在，我正在使用它，它将返回一个id值，但不是全部：

#!/usr/bin/env python
#-*- coding: utf-8 -*-

import json

json_data = open('jubjubProductions', 'r+')
jdata = json.loads(json_data.read().decode("utf-8"))

def id_generator(d):
    for k, v in d.items():
        if k == "id":
            yield v
        elif isinstance(v, dict):
            for id_val in id_generator(v):
                yield id_val

if __name__ == '__main__':
    for _ in id_generator(jdata):
        print (_)

Answer 1

def id_generator(dict_var):
    for k, v in dict_var.items():
        if k == "id":
            yield v
        elif isinstance(v, dict):
            for id_val in id_generator(v):
                yield id_val

这将创建一个迭代器，该迭代器将生成键“ id”下任意级别的每个值。用法示例（打印所有这些值）：

for _ in id_generator(some_json_dict):
    print(_)