字符串拆分为列而不是行

Question

样本数据：

id  email_address                                   email_new
-------------------------------------------------------------------------------
1   [e-mail]                      [e-mail]
2   [e-mail]; [e-mail]      [e-mail]
2   [e-mail]; [e-mail]      [e-mail]
3   [e-mail]; [e-mail]; [e-mail]  [e-mail]
3   [e-mail]; [e-mail]; [e-mail]  [e-mail]
3   [e-mail]; [e-mail]; [e-mail]  [e-mail]

我使用以下查询将’ ;‘’分隔的字符串分成几行：

SELECT
    id, email_address, email_new
FROM 
    (SELECT 
         id, email_address, 
         Split.a.value('.', 'NVARCHAR(max)') AS email_new 
     FROM
         (SELECT 
              id, email_address, CAST ('<M>' + REPLACE(email_address, '; ', '</M><M>') + '</M>' AS XML) email_new
          FROM 
              table) AS A 
     CROSS APPLY 
         email_new.nodes ('/M') AS Split(a)) x
GROUP BY
    id, email_address, email_new

我的查询存在问题，我不想为每个拆分的电子邮件地址创建新行-我想为其添加新列。

id  email_1                      email_2                email_3
------------------------------------------------------------------------------
1   [e-mail]   null                   null
2   [e-mail]         [e-mail]   null
3   [e-mail]                  [e-mail]            [e-mail]

email_address列中最多有3个单独的电子邮件地址。有什么建议？如果它的大小超过3，最好是答案可以占n列。

Answer 1

测试数据

Declare @t table (Id INT, email_address VARCHAR(1000) , email_new VARCHAR(100));
INSERT INTO @t VALUES
(1   ,'[e-mail]'                      , '[e-mail]'),
(2   ,'[e-mail]; [e-mail]'      , '[e-mail]'      ),
(2   ,'[e-mail]; [e-mail]'      , '[e-mail]'      ),
(3   ,'[e-mail]; [e-mail]; [e-mail]'  , '[e-mail]'               ),
(3   ,'[e-mail]; [e-mail]; [e-mail]'  , '[e-mail]'               ),
(3   ,'[e-mail]; [e-mail]; [e-mail]'  , '[e-mail]'      );

询问

WITH Emails (ID , XmlEmail, email_new)
AS
(
    SELECT Id
          , CONVERT(XML,'<Emails><email>'  
                    + REPLACE(email_address,';', '</email><email>') 
                    + '</email></Emails>') AS XmlEmail
          , email_new
      FROM @t
)

 SELECT   ID
        , XmlEmail.value('/Emails[1]/email[1]','varchar(100)') AS Email1
        , XmlEmail.value('/Emails[1]/email[2]','varchar(100)') AS Email2
        , XmlEmail.value('/Emails[1]/email[3]','varchar(100)') AS Email3
        , XmlEmail.value('/Emails[1]/email[4]','varchar(100)') AS Email4
        , XmlEmail.value('/Emails[1]/email[5]','varchar(100)') AS Email5
        , email_new
FROM Emails

结果

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